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Anton [14]
2 years ago
8

This is confusinggggg

Mathematics
1 answer:
MakcuM [25]2 years ago
8 0
In order to find the area of a circle. You need to find the radius of the circle, which is the diameter of the circle, halved. In your question all you do is half 62 which is 31, then do Area=pie x radius squared which is 3019.07 but then to give in 1DP the answer is
3019.1 hope this helps!! Mark me the brainiest!!



ANSWER- 3019.07

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I need help with this word problem it’s urgent please help.
harkovskaia [24]

Starting with some solution of volume <em>v</em> and an alcohol concentration of 100<em>c </em>% , if you add 180 mL of 45% isopropyl to it, you get a mixture with a total volume of 180 mL + <em>v</em>.

Each mL of the starting solution contains <em>c</em> mL of alcohol. For example, if the concentration of the starting solution is 80% (so <em>c</em> = 0.8), then each mL contains 80% = 0.8 of one mL of alcohol.

Similarly, each mL of the added solution with 45% concentration contains 0.45 mL of alcohol.

You want the new solution to have a concentration of 70%, so that the ratio of the amount of alcohol in it to the total volume is 70%, meaning

<em>cv</em> + 0.45 (180 mL) = 0.7 (180 mL + <em>v</em>)

and you want to solve for <em>v</em> :

<em>cv</em> + 81 mL = 126 mL + 0.7<em>v</em>

<em>cv</em> - 0.7<em>v</em> = 126 mL - 81 mL

(<em>c</em> - 0.7) <em>v</em> = 45 mL

<em>v</em> = (45 mL) / (<em>c</em> - 0.7)

Judging by context clues, <em>c</em> lies somewhere between 0.7 and 1. (It can't be less than 0.7 because mixing this solution with any other solution of smaller concentration will never yield a solution of higher concentration.)

If, for example, <em>c</em> = 0.8, so that your starting solution is at 80% concentration, then you would need

<em>v</em> = (45 mL) / (0.8 - 0.7) = 450 mL

to be mixed with 180 mL of 45% solution to end up with 180 mL + 450 mL = 630 mL of 70% solution.

As another example, if you're mixing pure alcohol, so that <em>c</em> = 1, you would need

<em>v</em> = (45 mL) / (1 - 0.7) = 150 mL

to make a 180 mL + 150 mL = 330 mL batch of 70% solution. The fact that you would need less of a higher concentration solution is not surprising.

3 0
2 years ago
In the following figure, the square ABCD is inscribed in the circle centered at point P. What is the area of the circle?
Ainat [17]

Answer:

A_{Circle} \approx 39.24\: units^2

Step-by-step explanation:

Square ABCD is inscribed in a circle with center P such that BC = 5 units.

BD will be diagonal of the square as well as diameter of the circle.

BD = BC\times\sqrt 2

\implies BD = 5\sqrt 2

-> Diameter of the circle (d) = 5\sqrt 2

-> Radius of the circle (r) = 2.5\sqrt 2=3.535\: units

A_{Circle} =\pi(r)^2

\implies A_{Circle} =3.14(3.535)^2

\implies A_{Circle} =3.14(3.535)^2

\implies A_{Circle} =39.2381465

\implies A_{Circle} \approx 39.24\: units^2

8 0
2 years ago
Brooke makes a design using 4-inch, 6-inch, and 9-inch pieces of string. Can Brooke make a triangle with her string?
Olin [163]
I really hope this is right, i don’t quite remember how to do these but i think c
6 0
2 years ago
The _____ is used to measure volume<br> 1) liter<br> 2) gram<br> 3) meter
tekilochka [14]
1 - liter
will be the answer
4 0
3 years ago
Read 2 more answers
2
goldfiish [28.3K]

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

h =8

r = 0.5

The volume is:

Volume = \pi r^2h

This gives:

V_A = \pi * 0.5^2 * 8

V_A = \pi * 2

V_A = 2\pi

For Can B, we have:

h =4

r = 1

The volume is:

Volume = \pi r^2h

This gives:

V_B = \pi * 1^2 * 4

V_B = \pi  * 4

V_B = 4\pi

So, we have:

V_A = 2\pi

V_B = 4\pi

By comparison, (d) is correct

4 0
3 years ago
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