Can someone help me plz

Mathematics

1 answer:

Naily [24]3 years ago

7 0

Answer:

x=70 y=110 z=30 is all of the variables

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Help me with this question below

lutik1710 [3]

See attached picture for steps and answer:

3 0

3 years ago

The perimeter of a rectangle is 150cm. The length is 15cm greater than the width. Find the dimensions

ANEK [815]

150/4 = 37.5cm. You divide by four because there are four sides on a rectangle. But 37.5 is the cm of a square. Since it says one of the sides is 15cm greater, you subtract 37.5 - 15 = 27.5cm on 2 of the width. While the other 2 lengths are greater than the width by 15 cm, so you add 15 to 37.5 which gives you 52.5cm. So the 2 width are 27.5cm and the length is 52.5cm.

7 0

3 years ago

F(x)=<img src="https://tex.z-dn.net/?f=%28x%2B1-%7Cx-1%7C%29%2F2" id="TexFormula1" title="(x+1-|x-1|)/2" alt="(x+1-|x-1|)/2" ali

katrin [286]

Answer:

$f(g(x))=\dfrac{|x|+1-||x|-1|}{2}$

Step-by-step explanation:

The most straightforward way is direct substitution of g(x) for x in f(x):

$f(g(x))=\dfrac{|x|+1-||x|-1|}{2}$

8 0

3 years ago

Please help. It’s a picture

Korolek [52]

$260

I don’t know what model/formula you are supposed to be using.

But what I did first was calculated what 30% of 2700$ is.
2700 x .3 = 810

So it depreciates $810 per year.

$810 x. 3 years = 2430

2700 - 2430 = 260

In three years, the laptop will be worth $260

6 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de

Lelechka [254]

Answer:

(a) $P(X=10) = 0.2070$

(b) $P(X\geq 10) = 0.3798$

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

$N = 50\\m = 30\\n = 15\\X = 10$