Answer:
Direction parabola opens upward.
Vertex of parabola is (27,-9).
Axis of symmetry is 
.
Step-by-step explanation:
Note: Option sets are not correct.
The vertex form of a parabola is
...(1)
where, (h,k) is vertex and x=h is the axis of symmetry.
If a<0, then parabola opens downward and if a>0, then parabola opens upward.
The given function is
...(2)
On comparing (1) and (2), we get
, so direction parabola opens upward.
, so vertex of parabola is (27,-9).
So, axis of symmetry is .
X would be 0 while Y would be 4
3x+y=4
-(2x+y=4)
----------------
x=0
Plug in x to any of those two equations in their original form
3(0)+y=4
0 + y = 4
y = 4
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
