Umm I didn't get a domain.... No solutions were found...
-16t^2 + v0t + h0
= -16(t^2 - 1/16 v0t) + h0
= -16 [(t - 1/32v0)^2 - (1/32 v0)^2 ) + h0
= -16(t - 1/32v0)^2 + 1/64 (v0)^2 + h0 which is the vertex form
The vertex is at the point (1/32v0, 1/64 (v0)^2)
1/32v0 represents the time when the firework is at its maximum height and 1/64 (v0)^2 is this maximum height
ANSWER
Yes,the graph passes the vertical line test.
EXPLANATION
The graph above shows a function because if we draw a vertical line across the graph anywhere, it will never intersect the graph more than once.
This is what we call the vertical line test.
Since the graph of the function passes the vertical line test, the graph shows a function.
See graph
Therefore the correct answer is option C.
Answer:
AC = √105 ≈ 10 cm (nearest whole number)
Step-by-step explanation:
Use Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse of a right triangle)
Give one of the legs = 4cm and the hypotenuse = 11 cm:
⇒ 4² + AC² = 11²
⇒ 16 + AC² = 121
⇒ AC² = 121 - 16
⇒ AC² = 105
⇒ AC = ±√105
As distance is positive, length of AC = √105 ≈ 10 cm (nearest whole number)