A group of friends spent 1, 0, 2, 3, 4, 3, 6, 1, 0, 1, 2, and 2 hours online last night. What are the 1st and 3rd quartiles for
charle [14.2K]
1 and 3 i just did the math tell me if i’m wrong
Answer:
Step-by-step explanation:
Given
Represent Goldfish with g and hermit crabs with h.
The first statement, we have:
The second statement, we have:
Required
Determine the selling price of 6 goldfish and 4 hermit crabs
The equations are:
--- (1)
--- (2)
Make g the subject in (2)
Divide both sides by 4
Substitute 
for g in (1)
Multiply through by 4
Open bracket
Collect Like Terms
Make h the subject
Substitute 4 for h in
This implies that:
1 goldfish = $2
1 hermit crab = $4
The cost of 6 goldfish and 4 hermit crabs is:
Since the order matters, it's a permutation of 7 letters, but mind you in
MOROCCO. you have 3 O's and 2 C's, Hence the arrangements are:
⁷P₇ /(3!2!) = 7!/(3!2!) = 5040/(3!2!) = 420 arrangements
Answer:
17
Step-by-step explanation:
Here in this question for finding the numbers that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively we have to first subtract the remainder of the following. By this step we find the highest common factor of the numbers.
And then the required number is the HCF of the following numbers that are formed when the remainder are subtracted from them.
Clearly, the required number is the HCF of the numbers 398−7=391,436−11=425, and, 542−15=527
We will find the HCF of 391, 425 and 527 by prime factorization method.
391=17×23425=52×17527=17×31
Hence, HCF of 391, 4250 and 527 is 17 because the greatest common factor from all the numbers is 17 only.
So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
Note: - whenever we face such a type of question the key concept for solving this question is whenever in the question it is asking about the largest number it divides. You should always think about the highest common factor i.e. HCF. we have to subtract remainder because you have to find a factor that means it should be perfectly divisible so to make divisible we subtract remainder. because remainder is the extra number so on subtracting remainder it becomes divisible.
Answer:
29
Step-by-step explanation:
