Answer:
28/7
Step-by-step explanation:
Answer:
The answer is Tonya's phone had the greater initial trade-in value.
Leo's phone decreases at an average rate slower than the trade in value of Tonya's phone.
Step-by-step explanation:
Given
Tonya

Leo




Solving (a): The phone with greater initial value
The initial value is when x = 0. So, we have:




From Leo's table

By comparison;

i.e.

<em>So: Tonya's had the greater initial trade-in value</em>
Solving (b): The phone with lesser rate
An exponential function is:

Where:

For Tonya

For Leo, we have:


So, the equation becomes:

and 
Solving
, we have:



becomes

Divide both sides by 480

Take square roots

-- Leo's rate
By comparison; Leo's rate is slower i.e. 0.87 < 0.88
Okay. You have 15 lbs of concrete, and x bags that can individually hold 2.5 lbs. What you need to do is divide 15 by 2.5, and the quotient will be 6.
Problem: 15 ÷ 2.5 = 6
So the answer to your problem will be: 6 bags.
Answer:
300 seconds
Step-by-step explanation:
The first dog run at v₁ = 15 m/sec the second one run at v₂ = 12 m/sec
we know that d = v*t then t = d/v
Then the first dog will take 300/ 12 = 25 seconds to make a turn
The second will take 300 / 15 = 20 seconds to make a turn
Then the first dog in 12 turns 12*25 will be at the start point, and so will the second one at the turn 15.
To check first dog 12 * 25 = 300
And the second dog 15 * 20 = 300
That means that time required for the two dogs to be at the start point together is
300 seconds, in that time the first dog finished the 12 turns, and the second had ended the 15.
Another procedure to solve this problem is as follows:
between 12 m/sec and 15 m/sec the minimum common multiple is 300 ( 300 is the smaller number that accept 12 and 15 as factors 12*15 = 300) Then when time arrives at 300 seconds the two dogs will be again in the starting point
I just answered this xD
1-3 is given as an example.
4. True
5. False. It is the same thing twice
6. True