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mr Goodwill [35]
3 years ago
14

How many ways can 10 runners finish first, second, and third in a race?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
4 0
Let's call the 10 runners A B C D E F G H I J
ABC
ABD
ABE
ABF
ABG
ABH
ABI
ABJ
ACB
ACD
ACE
ACF
ACG
ACH
ACI
ACJ
ADB
ADC
ADE
ADF
ADG
ADH
ADI
ADJ
AEB
AEC
AED
AEF
AEG
AEH
AEI
AEJ
AFB
AFC
AFD
AFE
AFG
AFH
AFI
AFJ
AGB
AGC
AGD
AGE
AGF
AGH
AGI
AGJ
AHB
AHC
AHD
AHE
AHF
AHG
AHI
AHJ
AIB
AIC
AID
AIE
AIF
AIG
AIH
AIJ
AJB
AJC
AJD
AJE
AJF
AJG
AJH
AJI
The above is 60 different ways, but now B C D E F G H I J have to come first, and the proses starts again, until we have covered them all. I'm not going to write them all out but in theory, there is 540 different ways. 9*60=540.
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x^3-x^2-17x+12

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use the graph to determine the domain and range of the relation and state whether the relation is a function
Alex

Answer:

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Step-by-step explanation:

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A,B,C

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Un capital de 4000 lei este plasat în regim de dobândă simplă pe o perioadă de 3 ani cu rata dobânzii
9966 [12]

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960

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I = P*r*t

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Veseljchak [2.6K]

Answer:

63.5

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The diagonals of a rhombus bisect opposite angles.

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You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

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2 years ago
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