m=18 when r = 2.
Step-by-step explanation:
Given,
m∝
So,
m = k×,--------eq 1, here k is the constant.
To find the value of m when r = 2
At first we need to find the value of k
Solution
Now,
Putting the values of m=9 and r = 4 in eq 1 we get,
9 = 
or, k = 36
So, eq 1 can be written as m= 
Now, we put r =2
m = 
or, m= 18
Hence,
m=18 when r = 2.
Answer:
$65.325 or $65.33
Step-by-step explanation:
When looking for a percentage in a number, you want to multiply that number by the percentage. Remember that all percentages are to the hundreth power, or 0.00. So if you want to find 30% of 50.25, you multiply it by 0.30 or 0.3. After calculating that you will come up with 15.075 as the percentage. Since the store is marking the price up, you add it to the original price. So your equation is 50.25 + 15.075 =?. After calculating that, you get the answer 65.325. That is only half of your answer though because, when dealing with money, you always round to the nearest hundredth. So when you round 65.325, you get 65.33 which should be the correct answer.
4/5-3/7. First they need the same denominater: 4/5(7)=28/35, 3/7(5)=15/35. 28/35-15/35. Now subtract numerators: 28-15=13. So your answer H. 13/35 :)
Let us start with assuming the amount of coffee worth $20 a pound to be "x" pounds.
Now she wants to mix "x" pounds of $20 coffee with 70 pounds of $90 coffee.
So the mixture would be (x + 70) pounds.
And the value of mixture would be = 20·x + (90)·(70) = (20x + 6300) dollars.
She want to sell this mixture at rate of $30 a pound. Her earning would be = 30·(x + 70) = (30x + 2100) dollars.
We know that the value of mixture would be equal to her earnings.
30x + 2100 = 20x + 6300
30x - 20x = 6300 - 2100
10x = 4200
x = 420
So, 420 pounds of $20 coffee would be used.
<h3>Answer:</h3>
The rate of change in the 2nd 3-year interval is 3.375 times that in the 1st 3-year interval.
<h3>Explanation:</h3>
The exponential function tells you that each year values get multiplied by 1.5. Then after thee years, values are multiplied by 1.5³ = 3.375. This is true for all function values, including average rate of change. Whatever the rate of change is in years 0–3, it will be 3.375 times that in years 3–6.
The calculation performed by the graphing calculator confirms this:
... the average rate of change in years 3–6 is 160.3125; in years 0–3, it is 47.5.
The ratio of these average rate of cange values is 3.375.
