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Pepsi [2]
2 years ago
8

Nico uses a uniform probability model for an experiment using a deck of 40 cards. there are 10 blue cards, 10 red cards, 10 gree

n cards, and 10 yellow cards in the deck. cards will be drawn one at a time and then replaced in the deck before another card is drawn. he uses the probability model to determine the probability of drawing a green card or a red card. what is p(green or red)? enter your answer as a simplified fraction in the box.
Mathematics
1 answer:
FromTheMoon [43]2 years ago
8 0

Answer:

1/2

Step-by-step explanation:

Since there are 40 cards in total and 10 cards for each colour...the probability of drawing either a green card or red card will be 20/40 since there a are 20 green and red cards combined

Therefore the probability is 1/2

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Seraphina is driving two hours to visit her family. For the first hour, she traveled at a speed of 56 miles per hour. Then, in t
wel

Answer: 21.1 %

Step-by-step explanation:

4 0
3 years ago
£54,000 split ratio 1:3:8
Scrat [10]
There are 12 parts to the ratio (1 + 3 + 8 = 12).
Divide 54,000 by 12.
54,000/12 = 4,500
Now multiply for each part:
1 = 4,500
3 = 13,500
8 = 36,000

You can check by adding them up (4,500 + 13,500 + 36,000 = 54,000).

So the ratio is 4,500:13,000:36,000

Hope this helps =)
4 0
3 years ago
How many terms are there in a geometric series if the first term is 4, the common ration is 3 and the sum of the series is 160
Marina CMI [18]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
S_n=160
\end{cases}

\bf 160=4\left( \cfrac{1-3^n}{1-3} \right)\implies 160=4\left( \cfrac{1-3^n}{-2} \right)\implies 160=-2(1-3^n)
\\\\\\
160=2(3^n-1)\implies \cfrac{160}{2}=3^n-1\implies 80=3^n-1
\\\\\\
81=3^n~~
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^4=3^n\implies 4=n
3 0
3 years ago
Rectangle ABCD is congruent to rectangle. Which sequence of transformations could have been used to transform rectangle ABCD to
il63 [147K]
Rectangle ABCD was rotated 90° counterclockwise around the origin and then translated 8 units down.
7 0
3 years ago
Solve the following system of equations for a and for b:
viktelen [127]

Answer:

a=3\\b=1

Step-by-step explanation:

9a+3b=30\\8a+4b=28

Let's solve the second equation for a to later on replace it in the first equation.

8a+4b=28\\8a=28-4b\\a=\frac{28-4b}{8}

Now plug this into the first equation.

9a+3b=30\\9(\frac{28-4b}{8})+3b=30

Distribute the 9

(\frac{252-36b}{8}) +3b=30

Break down the fraction.

\frac{252}{8}-\frac{36b}{8}+3b=30

Simplify.

\frac{63}{2}-\frac{9}{2}b+3b=30

Subtract \frac{63}{2}

-\frac{9}{2}b+3b=30-\frac{63}{2}

Combine like terms.

\frac{-9+2*3}{2}b=\frac{30*2-63}{2}

\frac{-9+6}{2}b=\frac{60-63}{2}

\frac{-3}{2}b=\frac{-3}{2}

Muliply by the reciprocal or inverted fraction next to b.

(-\frac{2}{3})(-\frac{3}{2}) b=-\frac{3}{2}(-\frac{2}{3})

b=1

Now plug this value into any of the equations to find the value of a.

8a+4b=28\\8a+4(1)=28\\8a+4=28\\8a=28-4\\8a=24\\a=\frac{24}{8}\\ a=3

5 0
4 years ago
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