Answer:
v = 6
Step-by-step explanation:
Solve for v:
-8 (8 v + 1) - 2 = -394
-8 (8 v + 1) = -64 v - 8:
-64 v - 8 - 2 = -394
Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):
-64 v + (-8 - 2) = -394
-8 - 2 = -10:
-10 - 64 v = -394
Add 10 to both sides:
(10 - 10) - 64 v = 10 - 394
10 - 10 = 0:
-64 v = 10 - 394
10 - 394 = -384:
-64 v = -384
Divide both sides of -64 v = -384 by -64:
(-64 v)/(-64) = (-384)/(-64)
(-64)/(-64) = 1:
v = (-384)/(-64)
The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:
Answer: v = 6
Answer:
B. y=7x+3
Step-by-step explanation:
You find the changes of y over the changes of x. y sub 2 - y sub 1 divided by x sub 2 over x sub 1. So, 17 - 10 over 2 - 1 = 7. 3 is the y-intercept. y=7x+3
Answer:
325
Step-by-step explanation:
500×.35=175
500-175=325
Our water faucet leaked 3 2/6 liters of water every 3/5 of a hour.
We are to find the rate in liter per hour at which the water faucet leaked.
First, use the number of liters the water faucet leaked in 3/5 of a hour.
This is 3 2/6 = 20/6
Therefore, the number of liters of water faucet leaked in 1 hour is
(20/6) / (3/5)
Before we solve this, we should simplify,
20/6 can be simplified to 10/3
3/5 cannot be simplified
Then, we should modify our problem to use reciprocation instead of a complex fraction,
(10 • 5) / (3 • 3)
This equals 50/9
Now, solve 50/9 for 5.555555555556
This rounds to 5.6
Thus, the required rate at which the water faucet leaked is 5.6 liters per hour.
Answer:
%90
Step-by-step explanation:
Since a percentage is out of 100 just multiply 50 times 2 and do the same to the top which would be 90
