Why is the length of the base of the rectangle the same as the circumference of the circles in the net of a cylinder?

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

6 0

Answer:

The width of the rectangle is the same as the length of the cylinder (h). The area of each of the two circles is \\ (\\pi r^2\\) and the area of the rectangle is \\ (2 \\pi r times h\\).

Step-by-step explanation:

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Evaluate the following<br><br> (1.6 x 10 12) ÷ (8.01 x 10 23)

devlian [24]

To evaluate the given expression, we must follow the rules of PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction) in solving.

Therefore, first calculate what's inside the parentheses:

(1619.2) / (8194.23)

Then perform the operation in between the parentheses:

<span>(1619.2) / (8194.23) = 0.20
</span>
Therefore the answer after evaluating the expression is 0.20.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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2 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$