Which angles are corresponding angles?

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago

The cooking class used 18 cups of flour to make 8 identical loaves of bread. How many cups of flour were needed for each loaf ?

Bas_tet [7]

What we need to do is divide 18 by 8 because 18 cups of flour makes 8 loaves of bread. By using a calculator, 18/8 = 2 1/4.

4 0

2 years ago

6)532 with a remainder

BartSMP [9]

Hello Rebelkid2004, 532 with a remainder is, gives remainder 0 and so are divisible by 1, we get factors of 532 numbers by finding numbers that can divide 532 without remainder or alternatively numbers that can multiply together to equal the target number being converted.

3 0

3 years ago

Identify the pattern and find the next number in the pattern. 0.8, 3.2 12.851.2

Savatey [412]

For this case we have the following sequence:
0.8
3.2
12.8
51.2
This sequence can be written as:
0.8 = 0.2 * 4 = 0.2 * 4 ^ 1
3.2 = 0.2 * 16 = 0.2 * 4 ^ 2
12.8 = 0.2 * 64 = 0.2 * 4 ^ 3
51.2 = 0.2 * 256 = 0.2 * 4 ^ 4
Therefore, we have that the generic expression for this case is:
an = 0.2 * 4 ^ n
Then, the next number is then:
a5 = 0.2 * 4 ^ 5 = 0.2 * 1024 = 204.8
answer
the next number in the pattern is 204.8

8 0

3 years ago

Will and Thomas are collecting baseball cards. Will already has ten baseball cards and plans to collect 5 cards per month. Thoma

andre [41]

I got 5 months, because you add on to each person frequency until you hit the same amount (sorry if it’s a sad answer)

5 0

2 years ago

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