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matrenka [14]
3 years ago
8

Triangle ABC has angles measuring 137°, 15°, and 28°. Classify the triangle by its angle measures.

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

Answer:12

Step-by-step explanation:hxdhvxrjjnvcxx

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Will mark branliest please help
Bad White [126]

Answer:

base =7.6 cm

Step-by-step explanation:

area of a triangle =base * height/2

=11.02*2 =base *height

22.04=base *2.9

22.04/2.9 =base

7.6 =base

3 0
2 years ago
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Alexa has, 2 nickels, 1 quarter, and 3 pennies. How much money does she have?
UkoKoshka [18]

Answer:

38 cents

Step-by-step explanation:

quarter= 25

nickles= 5

pennies= 1

5+5+25+3= 38

6 0
3 years ago
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1.) Multiply 2ab(−a+2b+3).(1 point)
GarryVolchara [31]

Answer:

(x+3)(4x−2)  =  4x2+10x−6

(x+2)(x2−3x +4) = x3−x2−2x+8

Step-by-step explanation:

8 0
3 years ago
Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer
Andrews [41]

Answer:

f(x) = \frac{24}{25} * \frac{5}{6}^x

Step-by-step explanation:

Given

(x_1,y_1) = (2,\frac{2}{3})

(x_2,y_2) = (3,\frac{5}{9})

Required

Write the equation of the function f(x) = ab^x

Express the function as:

y = ab^x

In: (x_1,y_1) = (2,\frac{2}{3})

y = ab^x

\frac{2}{3} = a * b^2 --- (1)

In (x_2,y_2) = (3,\frac{5}{9})

y = ab^x

\frac{5}{9} = a * b^3 --- (2)

Divide (2) by (1)

\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}

\frac{5}{9}/\frac{2}{3} = b

\frac{5}{9}*\frac{3}{2} = b

\frac{5}{3}*\frac{1}{2} = b

\frac{5}{6} = b

b = \frac{5}{6}

Substitute 5/6 for b in (1)

\frac{2}{3} = a * b^2

\frac{2}{3} = a * \frac{5}{6}^2

\frac{2}{3} = a * \frac{25}{36}

a = \frac{2}{3} * \frac{36}{25}

a = \frac{2}{1} * \frac{12}{25}

a = \frac{24}{25}

The function: f(x) = ab^x

f(x) = \frac{24}{25} * \frac{5}{6}^x

7 0
3 years ago
How many total inches are in 7 feet 4 inches and 4 feet 10 inches ??? A) 257 inches B) 130 inches C) 126 inches D) 146 inches wh
Gelneren [198K]
The correct answer is D, 146 inches.
7 x 12 = 84
4 x 12 = 48
84+48+4+10 = 146
5 0
3 years ago
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