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Ghella [55]
3 years ago
5

What is negative 7 minus negative 2

Mathematics
1 answer:
zalisa [80]3 years ago
3 0

Answer:

-5

Step-by-step explanation:

-7 - (-2)

-7 + 2

Example: If you owe someone $7, and you give them $2, how much do you still owe? You are owing him $7 so it's a negative and you give him $2 which is a negative as well since you are giving it to him. So, to answer how much do you still owe, you would add $2  to the $7 you owed, so now, you owe him $5, which is a negative since you OWE him.

Hope this helps:)

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What is the midpoint of the segment shown below?
Aneli [31]

Answer:

(1, -3/2)

Step-by-step explanation:

The x coordinate is the same for both endpoints so the x coordinate for the midpoint is 1

The y coordinate for the midpoint is found by adding the two y coordinates and dividing by 2

(2+-5)/2 = -3/2

The midpoint is

(1, -3/2)

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3 years ago
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Find the pattern. fill in the blanks. 251,351
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Answer:

451, 551, 651, 751, 851, 951, 1051, 1151,

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3 years ago
Brianna needs to rent a car while on vacation. The rental company charges $18.95, plus 15 cents for each mile driven. If Brianna
borishaifa [10]

Answer:

Step-by-step explanation:

First we subtract 18.95 from 50 to get 31.05. Then we divide our new number by .15 to get 207 which is your number of miles :)

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Expand and simplify bracket please quickly
natulia [17]

Answer:

4y²-1/4 is the required answer

Step-by-step explanation:

(2y -  \frac{1 }{2} )(2y +  \frac{1}{2} ) \\ using \: formula \:  {x}^{2}  - y {}^{2}  = (x - y)(x + y) \\ 4y {}^{2}  -  \frac{1}{4}

4 0
2 years ago
When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of
makkiz [27]

Answer:

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So A(t) \alpha \sin (\frac{t - \alpha }{k} )

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

A(t) = 2.2\sin \frac{(t)}{k} + 0.6

at t = 2 sec volume of a is 0.6

So function reduce to

A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6

and t = 5 max value of volume is represent

so,

\sin \frac{t - \alpha }{k} = 1

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\frac{6}{\pi } = k

so the equation becomes

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

7 0
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