I can't see what you are saying
Answer:
q = 5000/x + 6
Step-by-step explanation:
D´= dq/dx = - 5000/x²
dq = -( 5000/x²)*dx
Integrating on both sides of the equation we get:
q = -5000*∫ 1/x²) *dx
q = 5000/x + K in this equation x is the price per unit and q demanded quantity and K integration constant
If when 1006 units are demanded when the rice is 5 then
x = 5 and q = 1006
1006 = 5000/5 +K
1006 - 1000 = K
K = 6
Then the demand function is:
q = 5000/x + 6
This is what we already know:
![\left[\begin{array}{cccc} &YB&NB&total\\YF&45&[unknown]&146\\NF&[unknown]&[unknown]&[unknown]\\total&144&[unknown]&428\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%20%26YB%26NB%26total%5C%5CYF%2645%26%5Bunknown%5D%26146%5C%5CNF%26%5Bunknown%5D%26%5Bunknown%5D%26%5Bunknown%5D%5C%5Ctotal%26144%26%5Bunknown%5D%26428%5Cend%7Barray%7D%5Cright%5D%20%20%20)
And using this information, we can fill the table out. Remember that everything must add up to the total in the column and row. The complete table looks like this:
![\left[\begin{array}{cccc} &YB&NB&total\\YF&45&101&146\\NF&99&183&282\\total&144&284&428\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%20%26YB%26NB%26total%5C%5CYF%2645%26101%26146%5C%5CNF%2699%26183%26282%5C%5Ctotal%26144%26284%26428%5Cend%7Barray%7D%5Cright%5D%20)
Using the complete table, we see the fraction for students that only like baseball is 
and students who only like football is 
. All you need to do is add these fractions together to get your answer.
In short, 200 students only like one of the two sports.
Answer:
1)B= 3 ; standard form y = 4x/3 + 7/3 2)A= -7 ; standard form y = 7x -3
Step-by-step explanation:
1.) <em>We can substitute the coordinates of the known point of the line: </em>
-4x + By = 7 ; (-1,1)
-4(-1) + B(1) = 7
4 + B = 7
B = 7- 4 = 3
-4x + 3y = 7
y = (4x + 7)/3
Equation 1 in standard form:
1.) y = 4x/3 + 7/3
2.) <em>We can substitute the coordinates of the known point of the line: </em>
Ax + y = -3 ; (2,11)
A(2) + (11) = -3
2A + 11 = -3
2A = -3 -11 = -14
A = -14/2 = -7 coefficient A
-7x + y = -3
Equation 2 in standard form:
2.) y = 7x -3
Answers:
1) B= 3 ; standard form y = 4x/3 + 7/3 2) A= -7 ; standard form y = 7x -3
<h2><em>Spymore</em></h2>
