Since 3 squared is 9 and 4 squared is 16, the square root of 13 will fall somewhere between 3 and 4
Answer:
if repetition is allowed,
if repetition is not allowed.
Step-by-step explanation:
For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 =
possible passwords.
If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.
F(x) is a quadratic. The y intercept, therefore, is equal to the c value.
The y intercept here is -4.
For g(x), you can tell that the y intercept is 0 because that's the value of y when the x value is 0.
For h(x), the chart specifies that when x=0, y=-2, so the y intercept is -2.
Of these three values, 0 is the largest.
Final answer: g(x)
Answer:
See below and attached
Step-by-step explanation:
<u>As per the graph we have:</u>
- Coordinates of JL are J(-7, 4), L(-4, 0)
- Coordinates of MP are M(-10, 8), P(-1, -4)
<u>Slope formula is:</u>
<u>Slope of JL:</u>
- (0 - 4)/(-4-(-7)) = - 4 / 3
<u>Slope of MP:</u>
- (-4 -8)/(-1- (-10)) = -12 / 9 = - 4/3
Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)