A shopkeeper buys TVs for Nu 15000 and marks them up 15% to sell them. What is the mark up amount? *

1 answer:

6 0

$\\ \sf \longmapsto \: 15000 \times 15\% \\ \\ \sf \longmapsto \: 15000 \times \frac{15}{100} \\ \\ \sf \longmapsto \: 150 \times 15 \\ \\ \sf \longmapsto \: 2250$

Markup amount is 2250Nu

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A cashier is unsure whether a group of customers ordered and ate a large or a medium pizza. Medium pizzas have a diameter of 12

Vinvika [58]

Answer: large pizza

Work:

1) You can determine the arc of a slice that is 1/12 of the whole pizza using the diameter.

2) First, calculate the total circumference of each pizza.

Formula for the circumference: 2π×radius

radius = diameter / 2

medium pizza: 2π (12 / 2) = 12π ≈ 37.70 in

large pizza: 2π (16/2) = 16π ≈ 50.27 in

3) arc of a 1/12 sector

arc of a 1/12 sector = circumferece × 1/12

medium pizza: 37.70 in / 12 = 3.14 in

large pizza: 50.27 in / 12 = 4.19 ↔ this is pretty close to 4.25

So, at the end we have found that the sector of 4.25 in left belongs to a large pizza.

4 0

3 years ago

Rachael got a 550 on the analytical portion of the Graduate Record Exam (GRE). If GRE scores are normally distributed and have m

valina [46]

Answer:

Z=-2

This value means that the score of Rachel 550 it's 2 deviations below the mean of the population $\mu=600$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

$\mu=600$ represent the population mean for the Graduate Record Exam (GRE)

$\sigma=25$ represent the population standard deviation for Graduate Record Exam (GRE)

2) Solution to the problem

Let X the random variable that represent the Graduate Record Exam (GRE) of a population, and for this case we know the distribution for X is given by:

$X \sim N(600,25)$