Answer:
0.36
Step-by-step explanation:
Percentage of boys = 60%
Percentage of girls = 100 - 60 = 40%
Percentage of boys that arrive by car
= 20% of 60%
= 0.2 x 60 = 12%
Percentage of girls that arrive by car
= 60% of 40%
= 0.6 x 40
= 24%
Total Percentage of children arrive by car
= 12 + 24
= 36%
P(Arrive by car)
= 36%
= 0.36
A) 23/8 divide 23 by 8 to get 2 with remainder 7 therefore 2 7/8
work all by treating each fraction as a division problem and placing the remainder over the divisor
b) 14/3 = 4 2/3
c) 19/11 = 1 8/11
d) 8/7 = 1 1/7
e) 17/9 = 1 8/9
f) 27/8 = 3 3/8
g) 35/5 = 11 2/3
h) 9/4 = 2 1/4
Answer:

Step-by-step explanation:
Given
Poisson Distribution;
Average rent in a week = 2.3
Required
Determine the probability of renting no more than 1 apartment
A Poisson distribution is given as;

Where y represents λ (average)
y = 2.3
<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>
<em />
Using probability notations;

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]




Solving for P(X = 1) [substitute 1 for x and 2.3 for y]









Hence, the required probability is 0.331
Answer:
.214 if it is to 3 decimal places.