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asambeis [7]
3 years ago
7

Solve 3-x/2≥15 A.x ≤ -24 B.x ≤6 C.x ≥ -24 D.x ≥ -6

Mathematics
1 answer:
krek1111 [17]3 years ago
7 0
What she said hope that helps
You might be interested in
Plz help... geometry volume, density
Ivenika [448]

From what I'm understanding of these questions, the biggest thing you need to answer these is the formulas for cylinders and triangular prisms. I'm not sure what the quantities are for either question so I'm going to work with made up numbers to give examples for the formulas. For number 2 with the cylinder, let's consider the formula first:

π × r2 × h    <em>OR    </em>pi (3.14) times radius squared times height

If you have the height and you have pi, all you need to take is the doubled radius (aka multiply it by 2) and plug that back into the formula. For the sake of an example, I'm going to make up the number 2 for the radius and 6 for the height. Here's what that would look like:

r = 2; double it, resulting in 4

pi x 4^2 x 6

3.14 x 16 x 6

= 301.44

Work with the actual numbers you have and you're good to go.

For number 3, reducing something by 1/2 means dividing by 2. Let's consider the formula and then work through another example:

1/2 x b x h x l   <em>OR </em>   1/2 times base times height times length

For the sake of an example, I'll use 10 for the height, 15 for the base, and 20 for the length:

h = 10; reduce by 1/2, resulting in 5

1/2 x 15 x 5 x 20

= 750

Plug in your actual quantities, and remember your volume units. Hope this helps!

4 0
3 years ago
Solve the equation 4=t/2.5 t=
julia-pushkina [17]

Answer:

10

Step-by-step explanation:

Multiply 4 by 2.5 to get 10

8 0
3 years ago
Read 2 more answers
The table below shows the radius y, in inches, created by growing algae in x days: Time (x) (days) 1 4 7 10 Radius (y) (inches)
tatuchka [14]
PART A:
Given the table below showing the radius y, in inches, created by growing algae in x days.

Time (x) (days):          1       4        7        10
Radius (y) (inches):    1       8       11       12

We can find the find the correlation coeficient of the data using the table below:
\begin{center}&#10;\begin{tabular}&#10;{|c|c|c|c|c|}&#10;x & y & x^2 & y^2 & xy \\ [1ex]&#10;1 & 1 & 1 & 1 & 1\\&#10;4 & 8 & 16 & 64 & 32\\&#10;7 & 11 & 49 & 121 & 77\\&#10;10 & 12 & 100 & 144 & 120\\ [1ex]&#10;\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230&#10;\end{tabular}&#10;\end{center}

Recall that the correlation coefitient is given by the equation:
r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{ \sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)} }  \\  \\ = \frac{4(230)-(22)(32)}{ \sqrt{(4(166)-(22)^2)(4(330)-(32)^2)} } = \frac{920-704}{ \sqrt{(664-484)(1,320-1,024)}}  \\  \\ = \frac{216}{ \sqrt{180(296)}} = \frac{216}{ \sqrt{53,280} } = \frac{216}{230.8} =0.94

[Notice: even without using the formular to find the value of the correlation coeficient, it can be seen that the value of y strictly increases as the valu of x increases. This means that the value of the correlation coeficient is closer to +1 and from the options the value that is closest to +1 is 0.94]

From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

Recall the for the value of the correlation coeficient closer to +1, the relationship is strong positive, for the value closer to -1, the value is strong negative and for the values closer to zero, either way of zero is a weak positive if it is positive and weak negative if it is negative.


PART B:
Recall that the slope of a straight line passing through two points
(x_1,y_1) and (x_2,y_2)
is given by
m= \frac{y_2-y_1}{x_2-x_1}

Thus the slope of the graph of radius versus time between 4 and 7 days, [i.e. the line passes through points (4, 8) and (7, 11)] is given by
m= \frac{11-8}{7-4}= \frac{3}{3} =1

The value of the slope means that the radius of the algea grows by 1 inch evry day between day 4 and day 7.


PART C:
We can say that the data above represent both correlation and causationg.

Recall that correlation expresses the relationship between two variables while causation expresses that an event is as a result of another event.

From the information above, we have seen that there is a relationship (correlation) between the passing of days and the growth in the radius of the algae.

Also we can conclude that the growth in the radius of algae is a function of the passing of days, i.e. the growth in the radius of algae is as a result of the passing of days.

Therefore, <span>the data in the table represent both correlation and causation.</span>
6 0
3 years ago
C and D is not included cause I know they're not the answer
ycow [4]

Answer:

Graph B

Step-by-step explanation:

The <em>mass</em><em> </em>is independent, so it runs <em>horizontally</em>,<em> </em>and the <em>fuel</em> is dependent, so it runs <em>vertically</em>.

I am joyous to assist you anytime.

6 0
3 years ago
Find values of sine cosine tangent for
slava [35]

Answer:

The correct answer is option a

Sin A = 2√13/13

Cos A  = 3√13/13

Tan A = 2/3

Step-by-step explanation:

From the figure we can see that,a right angled triangle.

ΔABC

<u>To find side AB </u>

AB = √(AC)² + (BC)² =√(36² - 24² )= √1872

AC = 12√13

<u> To find the trigonometric ratio </u>

Sin A = BC/AB = 24/12√13  = 2√13/13

Cos A = AC/AB = 36/ 12√13  = 3√13/13

Tan A = BC/AC = 24/36 = 2/3

6 0
3 years ago
Read 2 more answers
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