Solve 3-x/2≥15 <br> A.x ≤ -24 <br> B.x ≤6<br> C.x ≥ -24<br> D.x ≥ -6

The lsrl after an exponential transformation is log yhat=.4785 + 1.468x. What is the exponential form of the regression?

zheka24 [161]

Answer:

$10^{0.4785+1.468x}=y$

Step-by-step explanation:

So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: $log(y)=0.4785+1.468x$ . And generally a logarithm can be written in the form $log_ba=c$ which can then be rewritten as $b^c=a$ , but since the log has no base, it's assumed to be 10. So in this case you have the equation:

$log_{10}y=0.4785+1.468x$ , which can then be written in exponential form as:

$10^{0.4785+1.468x}=y$

8 0

1 year ago

In recent commercials Toyota claimed that 80% of its vehicles sold in the past 20 years are still on the road. You work for an a

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We have to perform one sample proportion test. To do so we have to proceed through following steps.

(1) We have to collect data about vehicle sales in last 20 years.

(2) Using random number table or random number generator or otherwise we have to select sample of vehicles from the list of sale. In this step, we have to keep an eye on the fact that sample is to be selected from all years (all of 20). Using stratified random sampling by dividing vehicles sold over different years is an effective way to do so. That means, we may divide vehicles sold into 20 homogeneous strata over 20 years and select sample from each strata.

(3) After selecting sample of vehicles we have to communicate to corresponding vehicle owners to gather information about that particular vehicle.

(4) We have to note number of vehicles which are still on the road.

Suppose, we have selected n vehicles as sample and after communicating we found that \tiny r of those are still on the road.

We have to test for null hypothesis $H_0:p=0.80$