Answer:
a) P(X≥6) = 0.9614
b) P(7≤ X ≤9) = 0.628
c) P(X≤5) = 0.0386
Step-by-step explanation:
This can be solved using the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
Where p = probability of success
q = probability of failure = 1-p
n = number of trials
x = number of successful trials
We have p = 70% = 0.7
n = 12
a) Find the probability that the number who disapprove of smoking pot daily is no less than 6 i.e. P(X≥6). This can be calculated as:
P(X≥6) = 1 - P(X<6)
= 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)]
= 1 - [¹²C₀ (0.7)⁰(0.3)¹² + ¹²C₁ (0.7)¹(0.3)¹¹ + ¹²C₂ (0.7)²(0.3)¹⁰ + ¹²C₃ (0.7)³(0.3)⁹ + ¹²C₄ (0.7)⁴(0.3)⁸ + ¹²C₅ (0.7)⁵(0.3)⁷]
= 1 - (0.000000531 + 0.0000148 + 0.0001909 + 0.00148 + 0.00779 + 0.02911)
= 1 - 0.0386
P(X≥6) = 0.9614
b) P(7≤ X ≤9) = P(X=7) + P(X=8) + P(X=9)
= ¹²C₇ (0.7)⁷(0.3)¹²⁻⁷ + ¹²C₈ (0.7)⁸(0.3)¹²⁻⁸ + ¹²C₉ (0.7)⁹(0.3)¹²⁻⁹
= 0.158 + 0.231 + 0.239
P(7≤ X ≤9) = 0.628
c) P(X≤5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)
= ¹²C₀ (0.7)⁰(0.3)¹² + ¹²C₁ (0.7)¹(0.3)¹¹ + ¹²C₂ (0.7)²(0.3)¹⁰ + ¹²C₃ (0.7)³(0.3)⁹ + ¹²C₄ (0.7)⁴(0.3)⁸ + ¹²C₅ (0.7)⁵(0.3)⁷
P(X≤5) = 0.0386
Answer:
Step-by-step explanation:
You have what is called "perfect squares" so you can use the "difference of squares formula to factor:
So,
you can work the equation backward now and you will get your original equation.
9514 1404 393
Answer:
- 2/5 cups oats per cup water
- 2.5 cups water per cup oats
Step-by-step explanation:
The denominator of the fraction is the unit you want 1 of.
(6 cups oats)/(15 cups water) = (6/15) cups oats/(1 cup water)
= (2/5 cups oats)/(1 cup water)
1 cup of water would need 2/5 cups of oats.
__
Obviously, the other ratio is the reciprocal of this.
(1 cup water)/(2/5 cups oats) = (5/2 cups water)/(1 cup oats)
1 cup of oats would need 2.5 cups of water
Answer:
Your question isn't very specific.
The area of a trapezoid = ((sum of the bases) ÷ 2) • height
Trapezoid Diagonals: formulas are attached.
Step-by-step explanation:
5×3=15 so 15÷ 3=5, The answer to this question would be is 5.
