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mezya [45]
3 years ago
12

Robert and Chris can skate 4 miles in 18 minutes. How far can they ride in 45 minutes?​

Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer: Robert and Chris can skate 10 miles in 45 minutes.

Step-by-step explanation:

Let's start by finding the unit rate.

\frac{4}{18} =\frac{2}{9} \\\frac{18}{18} =1

Robert and Chris can skate \frac{2}{9} of a mile in 1 minute. Now we can multiply both by 45 to see how far the can go in 45 minutes.

(\frac{2}{9}) (\frac{45}{1} )\\\frac{(2)(45)}{(9)(1)} \\\frac{90}{9} \\10

45x1=45

The can skate 10 miles in 45 minutes.

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The system of equation used to find the Total number of flash cards made are \left \{ {{5x+5} \atop {6x}} \right..

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Step-by-step explanation:

Given:

Number of flash cards already made by Tristan = 5

Number of flash card Tristan makes in 1 min = 5

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We need to find the How long will Josh have same number of flashcards.

Also We need to find how many flashcards will each student have at that point.

Solution:

Let the number of minutes be'x'.

Now we can say that;

Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Tristan = 5+5x

Also We can say that;

Total number of flash cards made by Josh is equal Number of flash card Josh makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Josh = 6x

Hence the system of equation used to find the Total number of flash cards made are \left \{ {{5x+5} \atop {6x}} \right..

Now to find the number of minutes when both would have same number of flash cards we will make both the equation equal.

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On solving we get;

Combining like terms we get;

6x-5x=5\\\\x=5\ mins

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number of flash cards made by Tristan = 5x+5 = 5\times5+5=25+5=30

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Hence In <u>5 minutes</u>, each student will have <u>30</u> flash cards.

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