Eva sees a dolphin 3.2 meters below sea level and a bird 47/10 meters above sea level. Which of the following expressions repres
ents the vertical distance between the dolphin and the bird?
2 answers:
Answer:
Vertical distance between dolphin and the bird is 7.9 meters.
Step-by-step explanation:
Eva sees a Dolphin at the distance 3.2 meters below the sea level.
At the same time she sees a bird meters above the sea level.
Therefore, vertical distance between the dolphin and the bird = Distance of dolphin below the sea level + Distance of the bird above the sea level
= 3.2 +
= 3.2 + 4.7
= 7.9 meters
Answer is 7.9 meters.
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Answer: 6,987,000 pounds fo CO₂ per kWh.
Step-by-step explanation: <u>Quilowatt</u>-<u>hour</u> <u>(kWh)</u> is a unit of energy that measures the amount of energy expended in 1 hour.
The AC uses 850 Watts, which in kW is 850,000 kW
If you leave the AC on for 6 hours, it will consume
850,000(6) = 5,100,000 kWh
Eletricity produces 1.37 pounds of CO₂ per kWh, then in 5,100,000 kWh:
1.37 .(5,100,000kWh) = 6,987,000 pounds
If you open a window for 6 hours, you would keep 6,987,000 pounds of CO₂ for entering the atmosphere.
Answer:
a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.
b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.
c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.
d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean
Step-by-step explanation:
Problems of normally distributed distributions are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Probabilities:
A) Between 55,000 and 65,000 miles
This is the pvalue of Z when X = 65000 subtracted by the pvalue of Z when X = 55000. So
X = 65000
has a pvalue of 0.954
X = 55000
has a pvalue of 0.677
0.954 - 0.677 = 0.277
0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.
B) Less than 48,000 miles
This is the pvalue of Z when X = 48000. So
has a pvalue of 0.348
0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.
C) At least 41,000 miles
This is 1 subtracted by the pvalue of Z when X = 41,000. So
has a pvalue of 0.108
1 - 0.108 = 0.892
0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.
D) A lifetime that is within 10,000 miles of the mean
This is the pvalue of Z when X = 51200 + 10000 = 61200 subtracted by the pvalue of Z when X = 51200 - 10000 = 412000. So
X = 61200
has a pvalue of 0.889
X = 41200
has a pvalue of 0.111
0.889 - 0.111 = 0.778
0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean