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Mamont248 [21]
2 years ago
9

-7 2/3 + (-5 1/2) + 8 3/4

Mathematics
1 answer:
kolbaska11 [484]2 years ago
3 0
The answer is -4 5/12 negative four and five twelfths
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What is x? if u can’t see it the 2 other degrees are 32 and 120
Westkost [7]

Answer:28

Step-by-step explanation:

Since x+32 is 90 degrees, you subtract 32 from both sides to get the remaining which is 28 degrees.

8 0
2 years ago
If x = 3 cm and y = 2cm, what is the perimeter of the polygon
Virty [35]
Do you have a picture?? Maybe? I’m not good at these
4 0
3 years ago
A triangle has one 90-degree angle and one 38.7 - degree angle. What is the measure of the third angle?
tigry1 [53]
The answer is 51.3 degrees because you add 90+38.7=128.7
then you do 180-128.7 because this is a linear/ supplementary triangle which adds up to 180
and you get 51.3 degrees
4 0
3 years ago
The function y= -16t^2 +24t represents the height y (in feet) of a tennis ball bouncing straight up from the ground t seconds af
taurus [48]
We want to know the time, <em>t</em>, it takes the ball to reach a height (<em>y</em>) of 0.
0=-16t^2+24t
We can factor out the GCF first.  The largest number that will divide evenly into 16 and 24 is 8.  Also, both terms have a <em>t</em>, so we can factor that out as well:
0=8t(-2t+3) (-16/8 = -2 and 24/8 = 3)
Using the zero product property, we know that either 8t=0 or -2t+3=0.  Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.
5 0
3 years ago
Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]
sveta [45]

\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle

\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}

\implies\|\vec r'(t)\|=e^t\sqrt{65}

Then

s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t

3 0
3 years ago
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