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Ainat [17]
3 years ago
8

Create a model to show 2 x 5.

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

The model should look like this: ⚫⚫⚫⚫⚫

⚫⚫⚫⚫⚫

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7. An aquarium is shown below. The
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Answer:

1920 in³

Step-by-step explanation:

The volume of the water can be gotten by calculation the volume of the aquarium it fills/occupies.

Since the water fills to exactly three inches below the top of the  aquarium, hence the height of the water in the aquarium is given as:

height of water = 13 in - 3 in = 10 in

Therefore the volume of the water in the tank is given by the formula:

Volume of water = height of water * breadth of tank * length of tank

Volume of water = 10 in * 8 in * 24 in = 1920 in³

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6.3 The daily amount of coffee, in liters, dispensed by a machine located in an airport lobby is a random variable X having a co
dexar [7]

Answer:

a) 60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

b) 70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

c) 50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

The probability of X being higher than x is:

P(X > x) = 1 - \frac{x - a}{b-a}

The probability of X being between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

For this problem, we have that:

a = 7, b = 10

(a) at most 8.8 liters;

P(X \leq 8.8) = \frac{8.8 - 7}{10 - 7} = 0.6

60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

(b) more than 7.4 liters but less than 9.5 liters;

P(7.4 \leq X \leq 9.5) = \frac{9.5 - 7.4}{10 - 7} = 0.7

70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

(c) at least 8.5 liters.

P(X > 8.5) = 1 - \frac{8.5 - 7}{10 - 7} = 0.5

50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

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3 years ago
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