FIND sin0 WHERE 0 IS THE ANGLE SHOWN. GIVE AN EXACT VALUE, NOT A DECIMAL APPROXIMATION. Branliest

Mathematics

1 answer:

expeople1 [14]4 years ago

6 0

Answer:

$\frac{\sqrt{15} }{8}$

Step-by-step explanation:

We require to find the third side of the triangle.

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x represent the third side, then

x² + 7² = 8², that is

x² + 49 = 64 ( subtract 49 from both sides )

x² = 15 ( take the square root of both sides )

x = $\sqrt{15}$

Thus

sinΘ = $\frac{opposite}{hypotenuse}$ = $\frac{\sqrt{15} }{8}$

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