3 years ago

Help me please help me please

1 answer:

3 0

Step-by-step explanation:

where is the question? plz ss

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barxatty [35]

6-3=3
2/8-5/8=3/8
you would have to change the denominator

5 0

3 years ago

Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

$Length\times breadth\\\\=36\times 12\\\\=432\ cm^2$

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0

3 years ago

ExtremeBDS [4]

Y=180-69=111
4x+7=y
4x+7=111
4x=111-7
4x=104
X=26

Answer: x=26, y=111

4 0

4 years ago

Rainbow [258]

Answer:c

Step-by-step explanation:

7 0

3 years ago

o-na [289]

Are u at school dude do it yourself kjsnfhbagyuhfva

8 0

3 years ago

Help me please help me please ​