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3 years ago

14

Someone please help me with this questions

1 answer:

insens350 [35]3 years ago

7 0

Answer:

Coefficient Is the small 2

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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

Veronika [31]

Answer:

f(x) = one eighth (x − 3)2 − 3

or C is your answer.

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3 years ago

The value of cube root of x^10, when x = -2, can be written in simplest form as a^3 times the square root of b, where a = _____

Montano1993 [528]

Answer:

$a = 2$

$b = 2^{1/6}$

Step-by-step explanation:

Given

$\sqrt[3]{x^{10}} = a^3 * \sqrt b$

$x = -2$

Required

Find a and b

We have:

$\sqrt[3]{x^{10}} = a^3 * \sqrt b$

Substitute -2 for x

$\sqrt[3]{(-2)^{10}} = a^3 * \sqrt b$

$\sqrt[3]{1024} = a^3 * \sqrt b$

Expand

$\sqrt[3]{2^9 * 2} = a^3 * \sqrt b$

Split the exponents

$2^{(9/3)} * 2^{(1/3)} = a^3 * \sqrt b$

$2^{3} * 2^{1/3} = a^3 * \sqrt b$

By comparison:

$a^3 = 2^3$

So;

$a = 2$

and

$\sqrt b = 2^{1/3}$

Take square roots of both sides

$b = 2^{1/6}$

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3 years ago

a line with a slope of 2 passes through (k,3) and (6,k) on the coordinate grid. what is the value of k?

kirill [66]

Answer:

k = 5

Step-by-step explanation:

Calculate the slope m and then equate to 2

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (k, 3) and (x₂, y₂ ) = (6, k)

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2(6 - k) = k - 3

12 - 2k = k - 3 ( subtract k from both sides )

12 - 3k = - 3 ( subtract 12 from both sides )

- 3k = - 15 ( divide both sides by - 3 )

k = 5

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3 years ago

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28 percent............

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3 years ago

Is 4,9,16 an arithmetic or geometric sequence?

BaLLatris [955]

I think it’s neither ??

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3 years ago