B.<span>Adding 15 to both sides of the equation.
A. Adding 8x to both sides wouldn't cancel anything out.
B. Adding 15 to both sides will cancel out 15 making it easier to solve for x.
C.Adding 3 to both sides will not cancel anything out.
D. Adding 2x to both sides won't cancel anything out. </span>
we know that
If two lines are perpendicular, then the product o their slopes is equal to minus one
so
Step 1
<u>Find the slope of the given line</u>
we have
-------> 
This line is parallel to the y-axis
so
the perpendicular will be parallel to the x-axis
Step 2
The equation of the line perpendicular to the given line is the y-coordinate of the given point
Point 
the equation is
therefore
<u>the answer is</u>
see the attached figure to better understand the problem
Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
<h3>
Step-by-step explanation:</h3>
<u>Pythagorus theorum:</u>
9² = 3² + YZ²
81 - 9 = YZ²
√72 = YZ
∴YZ= 8.48 ≈ 8.5
<u>Trigonometry:</u>
We have adjacent as 3, and hypotenuse as 9
cos X = 3/9
X= cos∧-1 (3/9) → <em>[cos inversed]</em>
∴X= 70.5°
We have opposite as 3 and hypotenuse as 9
sin Z= 3/9
Z= sin∧-1 (3/9)→<em> [sin inversed]</em>
∴Z= 19.47 ≈ 19.5
