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2 years ago

H SSS SAS ASA AAS HL cannot determine

Mathematics

1 answer:

malfutka [58]2 years ago

4 0

Answer:

last answer

Step-by-step explanation:

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To increase an amount by 3% what single multiplier would you use?

loris [4]

3% is the decimal 0.03 .

To make a number 3% bigger, multiply it by 1.03 .

The ' 1 ' part is the amount that's already there, and
the ' .03 ' part is the amount to be added onto it.

3 0

3 years ago

At First Class Pizza, 12% of the pizzas made yesterday were pepperoni pizzas. If 27 pizzas have pepperoni, how many pizzas were

gogolik [260]

Answer: 225

Step-by-step explanation:

Let the total number of pizza made be represented by x.

Therefore, the situation in the question can be written as:

12% × x = 27

12/100 × x = 27

0.12 × x = 27

0.12x = 27

Divide both side by 0.12

0.12x/0.12 = 27/0.12

x = 225

The total pizza made was 225.

3 0

2 years ago

What is the percentage of 48g of fat out of a 70g allowance

Elenna [48]

5 0

3 years ago

A box contains plain pencils and pens. A second box contains color pencils and crayons. One item from each box is chosen at rand

pochemuha

Answer:

1/2

Step-by-step explanation:

its 1 out of 2 chances

6 0

3 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

5 0

2 years ago