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saveliy_v [14]
3 years ago
14

Find the radius of a circle with 154cm2 ​

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

7 is your answer ..........

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Help me with this question please, thank you !
Salsk061 [2.6K]

Answer:

2

Step-by-step explanation:

[(27divided by (-3)-9] divided by [15-21}

=[-9-9] divided by 3

= 6divided by 3 = 2

<h2><u><em>if answer is correct so mark me as brain lest :-)</em></u></h2>

<u><em></em></u>

5 0
2 years ago
Answer quickly please &lt;3
sertanlavr [38]

Answer:

x is greater than -5

Step-by-step explanation:

3 0
3 years ago
Plz answer number 12 :)
TEA [102]
It’s a (the one on the top left), because the input and output values are correct in the table!
3 0
3 years ago
!50 POINTS! GIVE REAL ANSWER OR I REPORT PLZ NO TROLLS! An executive drove from his home at an average speed of 35 mph to an air
bixtya [17]

Answer:

it took him 3 hours to get to work

Step-by-step explanation:

For the first part of the trip, the executive covered a distance "d" in time 't" at 35 mph, therefore we can write that the time it took to get to the helicopter was:

t-\frac{d}{35}

which if the distance is in miles, will render the time in hours.

We can write something similar for the second part of the trip", using the same "t" since it took the same time as for the first one, and using for distance 169.5 - d (since it is the distance to complete the total traveled distance :

t=\frac{169.5-d}{78}

Now we equal those two equations because the time "t" is the same, and solve for "d":

\frac{d}{35} =\frac{169.5-d}{78} \\78\,d=35\,(169.5-d)\\78\,d=5932.5-35\,d\\(78+35)\,d=5932.5\\d=\frac{5932.5}{113} \\d=52.5

Now, knowing the distance covered in the first trip, we can find the time of that first trip:

t=\frac{52.5}{35} =1.5\,\,hours

Therefore, the time it took for thye total trip is: 1.5 h + 1.5 h = 3 hours

7 0
3 years ago
find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
charle [14.2K]

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

8 0
4 years ago
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