1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KatRina [158]
3 years ago
11

find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

You might be interested in
Find the solution to the system 4x - y = -12 and -x - y = 3
nikdorinn [45]

Answer:

x = -3 , y = 0

Step-by-step explanation:

Solve the following system:

{4 x - y = -12 | (equation 1)

-x - y = 3 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{4 x - y = -12 | (equation 1)

0 x - (5 y)/4 = 0 | (equation 2)

Multiply equation 2 by 4/5:

{4 x - y = -12 | (equation 1)

0 x - y = 0 | (equation 2)

Multiply equation 2 by -1:

{4 x - y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Add equation 2 to equation 1:

{4 x+0 y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Divide equation 1 by 4:

{x+0 y = -3 | (equation 1)

0 x+y = 0 | (equation 2)

Collect results:

Answer: {x = -3 , y = 0

8 0
4 years ago
Find the slope of each line.<br> 1)<br> ا ا ا ا ا ا ا ا
kirza4 [7]

Answer:

1111111 is the answer

Step-by-step explanation:

8 0
3 years ago
If 2x^2 + 6x = 36 what are the possible values of x? specifically 2 answers?
OLga [1]

Step-by-step explanation:

2x^2+6x=36

x^2+3x=12

x^2+3x-12=0

x=(-3+(57)^0.5)/2 or x=(-3-(57)^0.5)/2

8 0
3 years ago
Given the system has no solution, find the value of a/b. Show your work.
Lana71 [14]
It’ll be C or B with no soul took by finding the value.
8 0
3 years ago
Read 2 more answers
There is a photo attached
natulia [17]

You can use the sum of angles identities, then rearrange to put the result in the form of tangents.

\displaystyle\frac{\sin{(x+y)}}{\sin{(x-y)}}=\frac{\sin{(x)}\cos{(y)}+\cos{(x)}\sin{(y)}}{\sin{(x)}\cos{(y)}-\cos{(x)}\sin{(y)}}\\\\=\frac{\left(\frac{\sin{(x)}\cos{(y)}+\cos{(x)}\sin{(y)}}{\cos{(x)}\cos{(y)}}\right)}{\left(\frac{\sin{(x)}\cos{(y)}-\cos{(x)}\sin{(y)}}{\cos{(x)}\cos{(y)}}\right)}\\\\=\frac{\tan{(x)}+\tan{(y)}}{\tan{(x)}-\tan{(y)}}

6 0
4 years ago
Other questions:
  • If justin has 90 tacos and loses 15 how many does he have
    14·2 answers
  • Cos xcos y=1/2(sin(x+y)+ sin(x-y))
    12·1 answer
  • (Will give brainliest to correct answer)
    7·1 answer
  • PLEASE HELP I WILL BRAINLIEST, MY GPA RELIES ON THIS!! IM BEGGING HERE
    15·1 answer
  • Find the volume of the figure. Use 3.14 for pi
    13·1 answer
  • What is 0+0 plz help me o am in college and need help
    10·2 answers
  • 1 -sin^2x÷csc^1x=sinx^2<br>​
    9·1 answer
  • Solve for y math problem
    14·1 answer
  • Mr. Perez brought his daughter and her friends to
    12·1 answer
  • Please help me volume is 9881.25 but yeah please help mee
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!