Explanation:
It is known that relation between 
, 
, and pH is as follows.
![E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}] ](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%28%5Cfrac%7B0.0591%7D%7Bn%7D%29%20%5Ctimes%20log%5BH%5E%7B%2B%7D%5D%0A)
Also, it is known that for hydrogen is equal to zero.
Hence, substituting the given values into the above equation as follows.
0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}]
[/tex]
![-log[H^{+}]](https://tex.z-dn.net/?f=-log%5BH%5E%7B%2B%7D%5D)
= 4.03
![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
= antilog 4.03
= 3.5
As, pH = .
Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.
Answer:
a. 0.026 M
Explanation:
Molarity is a measure of the molar concentration of a solution. It can be calculated by using the following formula:
Molarity = n/V
Where;
n = number of moles (mol)
V = Volume of solution (L)
Based on the information provided;
V = 23.2mL = 23.2/1000 = 0.0232 L
n = ?
To get the number of moles of KHP, we use the formula:
mole = mass/molar mass
mole (n) = 0.123/204.2
mole (n) = 0.0006024mol
Molarity = n/V
Molarity = 0.0006024 ÷ 0.0232
Molarity = 6.024 × 10^-4 ÷ 2.32 × 10^-2
Molarity = 6.024/2.32 × 10^(-4--2)
Molarity = 2.59 × 10^-2
Molarity = 0.026 M
