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MAVERICK [17]
3 years ago
15

In this experiment, you used phenolphthalein to monitor the neutralization reactions. describe the chemical differences between

an equivalence point and an endpoint in titration and use this to explain whether phenolphthalein could be used as an indicator in any acid/base neutralization.
Chemistry
1 answer:
viva [34]3 years ago
6 0
The endpoint in tiration is the point where an indicatior's halfway thru its color change. Equivalence point is where moles/stoichiometry of the system is satisfied (moles of reactants are equal to each other).

Titrating a strong acid with a strong base results in a salt that is neutral. Phenolphthalein changes color in the range <span>8.3 – 10. It is very easy to spot the change as it is colorless in acidic (< 8.3) and pink in basic (> 10).

pH will rapidly change near titration equivalence point. </span><span>Only one drop of the titrant causes this large change, the color change of phenolphthalein does not occur on the equivalence point, but IT IS within about 1 drop. <span>It would be considered an "acceptable uncertainty" in using titration to determine concentration by volumetric measurement.</span></span>

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A scientist finds that a sample of matter contains three types of atoms. The sample can be any of the following, except:
GrogVix [38]

Answer:

The correct answer is C. element

Explanation:

The sample cannot be an element because an element - or <em>elemental substance</em> - cannot be decomposed into simpler substances. Thus, it cannot be composed by differents types of atoms. For example, an element is carbon (C).

As the sample contains <u>three types of atoms</u>, it can be a compound, a molecule or a mixture, because they can be composed by different types of atoms - of different chemical elements. For example, the sample could contain the element carbon (C) combined with other elements, for example oxygen (O) or hydrogen (H), amoing others.

6 0
3 years ago
How does advertising affect the sales of orbit white
MAXImum [283]
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I hope I didn't misread the question because this looks more like an English/ Social Studies question than a chemistry question.
3 0
3 years ago
Read 2 more answers
A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

5 0
3 years ago
20.00 g of aluminum (al) reacts with 78.78 grams of molecular chlorine (cl2) all of each reactant is completely consumed and a s
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The word equation is

aluminum + chlorine → product

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8 0
3 years ago
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Ede4ka [16]

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8 0
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