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MAVERICK [17]
3 years ago
15

In this experiment, you used phenolphthalein to monitor the neutralization reactions. describe the chemical differences between

an equivalence point and an endpoint in titration and use this to explain whether phenolphthalein could be used as an indicator in any acid/base neutralization.
Chemistry
1 answer:
viva [34]3 years ago
6 0
The endpoint in tiration is the point where an indicatior's halfway thru its color change. Equivalence point is where moles/stoichiometry of the system is satisfied (moles of reactants are equal to each other).

Titrating a strong acid with a strong base results in a salt that is neutral. Phenolphthalein changes color in the range <span>8.3 – 10. It is very easy to spot the change as it is colorless in acidic (< 8.3) and pink in basic (> 10).

pH will rapidly change near titration equivalence point. </span><span>Only one drop of the titrant causes this large change, the color change of phenolphthalein does not occur on the equivalence point, but IT IS within about 1 drop. <span>It would be considered an "acceptable uncertainty" in using titration to determine concentration by volumetric measurement.</span></span>

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An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a sol
Harman [31]
Answer is: <span>the volume percentage of ethylene glycol in the solution is 43.1%.
V(solution) = 1 m</span>³.
d(solution) = 1050 kg/m³.
m(solution) = 1050 kg.
d(ethylene glycol) = 1116 kg/m³.
d(water) = 1000 kg/m³.
m(solution) = d(ethylene glycol) · V(ethylene glycol) + d(water) · V(water). 
V(ethylene glycol) = 1m³ - V(water).
1050 kg = 1116 kg/m³ · (1m³ - V(water)) + 1000 kg/m³ · V(water).
1050 kg = 1116 kg - 1116·V(water) + 1000·V(water).
116 kg/m³ ·V(water) = 66kg.
V(water) = 0.569 m³.
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percentage = 0.431 m³ ÷ 1 m³ · 100% = 43.1%.

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4 years ago
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riadik2000 [5.3K]

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5 0
2 years ago
which would you think would be a stronger interaction and why: an interaction between a sodium ion and the prtial negative charg
Karo-lina-s [1.5K]

Answer:

The interaction between sodium ion and the partial negative charge on the oxygen is stronger.

Explanation:

The predominant interaction that exists between sodium ion and the partial negative charge on the oxygen is ion-dipole interaction.

The predominant interaction that exists between two ethanol molecules is hydrogen bonding interaction.

The order of strength of the intermolecular interactions in decreasing order:

Ionic bond > ion-dipole interaction > hydrogen bonding > dipole-dipole interaction > ion-induced dipole interaction > induced dipole- dipole interaction > london force

So, ion-dipole interaction is stronger than hydrogen bonding.

Hence, the interaction between sodium ion and the partial negative charge on the oxygen is stronger.

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blagie [28]

Answer:

The answer is attached below

Explanation:

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