Answer:

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Step-by-step explanation:
A pair of factors are two factors of a number, when multiplied, gives the number.


The pairs 3, 12 and 4, 9 are factor pairs of 36.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
1%
Step-by-step explanation:
S.P of each radio=$ 2288
Total S.P=
$4576
Gain=10%
Lose=10%
C.P=
C.P=
By using the formula
C.P of one radio=
$2080
C.P of another radio=
=$2542.2
Total C.P of two radios=2080+2542.2=$4622.2
Total C.P >Total S.P
Loss=S.P-C.P
Loss=4622.2-4576=$46.2
Loss%=
Loss %=
1%
Hence, his loss 1%
:Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleventh time, what is the probability that it will land on heads?
Solution:
The probability would be ½. The result of the eleventh toss does not depend on the previous
results.
Answer:

Step-by-step explanation:

= 
= 
= 
= 
So, the appropriate value to complete it is -1
#CMIIW ^^
it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666