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2 years ago

PLEASE HELP, I ONLY HAVE A FEW MINUTES TO TURN THIS IN BEFORE ITS NOT ACCEPTED!!

Mathematics

2 answers:

vaieri [72.5K]2 years ago

8 0

Answer:

$\Large \pink{\tt \dfrac{i dunno}{..}}$

Vadim26 [7]2 years ago

6 0

Answer:

The slope is 3, the y- intercept is -2, and the equation is y= 3x - 2

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Write this second order differential equation as a first order matrix-vector system of differential equations. Show your work in

Mkey [24]

Answer:

See explaination

Step-by-step explanation:

To convert a second-order differential equation into a system of linear differential equation, we have to write y'' as x', for some variable x.

please kindly see attachment for the step by step solution of the given problem.

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2 years ago

Determine the scale factor for triangle abc to triangle ab^ prime c^ prime a 20 ft 10 2 b. 10 c. 20 1/2

Sergio [31]

Answer: 2

Step-by-step explanation:

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2 years ago

Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)

givi [52]

$Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

Step-by-step explanation:

Since we have given that

$y=x^{8sinx}$

By using logarithmic on both sides we get,

$log y= 8 sinx. logx$

(∵ $log(a^m)=m.loga$ )

Now, differentiating on both sides ,we get,

$\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})$

$\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})$

$\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

6 0

2 years ago

distance is equal to 1300km av average speed is equal to 20 metre per second time is equal to what ?

AURORKA [14]

20 meter per second= 1200 m/h=1.5km/h
The time is 1300: 1.5 =866.66

3 0

2 years ago

Fraction multiplying by fractions

Amanda [17]

$\bf \cfrac{2}{9}\times a=\cfrac{3}{15}\implies \cfrac{2a}{9}=\cfrac{1}{5}\implies 2a=\cfrac{9\cdot 1}{15}\implies 2a=\cfrac{3}{5}
\\\\\\
a=\cfrac{3}{2\cdot 5}
\implies 
a=\cfrac{3}{10}\\\\
-------------------------------\\\\
\cfrac{2}{5}\times b=\cfrac{7}{12}\implies \cfrac{2b}{5}=\cfrac{7}{12}\implies 2b=\cfrac{5\cdot 7}{12}\implies 2b=\cfrac{35}{12}
\\\\\\
b=\cfrac{35}{2\cdot 12}\implies b=\cfrac{35}{24}$

3 0

2 years ago