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3 years ago

Can someone give me an example of transformation of electrical to mechanical energy

Mathematics

1 answer:

astra-53 [7]3 years ago

8 0

Answer:

i need this for a challenge

Step-by-step explanation:

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D =<br> = (x - x)*+(y - y)<br> +<br> TU = (4,1) (3,-1)<br> Answer:

RideAnS [48]

Answer:

Distance

2.23606797749979

Midpoint

(3.5,0)

Slope

x intercept

3.50

y intercept

−7.00

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?

lana66690 [7]

Answer:

(1,1)

Step-by-step explanation:

3 0

3 years ago

Shelly is tying to improve her running time for track race. She ran the first race 43.13 seconds. Her time was 43.1 seconds in t

grandymaker [24]

Answer:

42.77

Step-by-step explanation:

The pattern is taking away 0.3. 43.07 minus 0.3 equals 42.77

3 0

3 years ago

Ben scores 56 out 0f 79 marks in a maths test?

zimovet [89]

<h3>Answer: 70.9%</h3>

Work Shown:

56/79 = 0.70886 approximately

Move the decimal point 2 spots to the right to go from 0.70886 to 70.886%

That rounds to 70.9%

3 0

2 years ago

Read 2 more answers

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago