Answer: No, we don't have a right triangle
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Explanation:
If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.
Here we have a = 2, b = 5 and c = 7.
So...
a^2+b^2 = c^2
2^2+5^2 = 7^2
4+25 = 49
29 = 49
The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do <u>not</u> have a right triangle.
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In contrast, consider the classic 3-4-5 right triangle
a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).
The answer would be 44,800 if you want to round the hundreds place
Step-by-step explanation:
if x=1/4 then y=1/4-1/4=0
if x=13/4 then y=13/4-1/4=12/4=3
if x=2 then y=2-1/4=8/4-1/4=7/4=1 3/4
Answer:
False.
Step-by-step explanation:
If we substitute a for 6, the inequality would become 6 > 6. That is not true because 6 cannot be greater than itself.
Okay so the answer would be
