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LiRa [457]
2 years ago
14

PLEASE HELP: Find the measure of each angle in the isosceles

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
3 0

Answer:

gtntt4bgt4thn

Step-by-step explanation:

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Dina took 12 hours to read a 600 page book What was her page per minute rate?
jok3333 [9.3K]

50 divide to find the answer

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2 years ago
What is the radius and diameter of the following circle?
d1i1m1o1n [39]

Answer:

radius=7.5, diameter=13

Step-by-step explanation:

diameter is the length across a circle through the middle, and it is given in the picture. radius is half of the diameter

8 0
2 years ago
Simple math but I can't seem to understand it: x+y=2 becomes y=2-x, in order to find slope and y intercept y=mx+b The result bec
IgorLugansk [536]

Answer:

See below.

Step-by-step explanation:

So we started off with the equation:

x+y=2

And we subtracted x from both sides to acquire:

y=2-x

Now, this is essentially slope-intercept form. Recall that the slope-intercept form is:

y=mx+b

Where m is the slope and b is the y-intercept.

If we rearrange our equation:

y=2-x\\y=-x+2

And put some parentheses:

y=(-1)x+(2)

We can see that this is indeed slope-intercept form.

And we can see that m is -1 and b is 2.

In other words, the slope is -1 and the y-intercept is 2.

3 0
3 years ago
Read 2 more answers
What is the derivative of cosx
grandymaker [24]
-sinx + C
hope this helps!
7 0
2 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
2 years ago
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