Question

Need some help! help giving 10 points ​

Answer 1

Answer:

The remaining lenghts are $x = 20.364\,cm$ and $y = 12.925\,cm$.

Step-by-step explanation:

Given that there are two triangles opposite to each other and between two parallel lines, then both are similar, meaning than following relationships exist:

$\frac{AC}{CD} = \frac{BC}{CE} = \frac{AB}{DE}$ (1)

If we know that $AC = 11\,cm$, $CD = 28\,cm$, $BC = 8\,cm$ and $DE = 32.9\,cm$, then the missing lengths are, respectively:

$\frac{11\,cm}{28\,cm} = \frac{8\,cm}{x}$

$x = \frac{(28\,cm)\cdot (8\,cm)}{11\,cm}$

$x = 20.364\,cm$

$\frac{11\,cm}{28\,cm} = \frac{y}{32.9\,cm}$

$y = \frac{(11\,cm)\cdot (32.9\,cm)}{28\,cm}$

$y = 12.925\,cm$

The remaining lenghts are $x = 20.364\,cm$ and $y = 12.925\,cm$.