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adelina 88 [10]
3 years ago
13

Need help ASAP please thankyou!

Mathematics
1 answer:
Ilya [14]3 years ago
6 0

Answer:

<em>c=7</em>

<em>d=5</em>

Step-by-step explanation:

<u>Exponential Equations</u>

We need to recall some properties of exponentials to solve the equations:

x^a*x^b=x`{a+b}

\displaystyle (x^a)^b=x^{ab}

Equation A

\sqrt{448x^c}=8x^3\sqrt{7x}

Squaring:

(\sqrt{448x^c})^2=(8x^3\sqrt{7x})^2

Simplifying the radicals:

448x^c=64x^6(7x)

448x^c=448x^7

If follows that

c=7

Equation B

\sqrt[3]{576x^d}=4x\sqrt[3]{9x^2}

Raising to the third power:

(\sqrt[3]{576x^d})^3=(4x\sqrt[3]{9x^2})^3

576x^d=4^3x^3(9x^2)

Operating

576x^d=64x^3(9x^2)=576x^5

Thus:

d=5

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