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GREYUIT [131]
2 years ago
7

Write the equation 2x + 4y = 12 in slope intercept form.

Mathematics
1 answer:
Gwar [14]2 years ago
7 0
4y=12-2x
y=(12-2x)/4
-------------
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Alma wants to buy socks. She has $11.00 and the socks cost $3.00 per pair. How many pairs of socks can Alma buy? How much money
Llana [10]

Answer:

She can buy 3 pairs for $9.00 with $2.00 extra.

Step-by-step explanation:

4 0
2 years ago
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Find an equation of the line having slope -2 that passes through the point (1, 5)
Alenkasestr [34]
Slope of -2, (1,5)

y = mx + b
slope(m) = -2
(1,5)...x = 1 and y = 5
now we sub and find b, the y int
5 = -2(1) + b
5 = -2 + b
5 + 2 = b
7 = b
so ur equation is : y = -2x + 7

The approximation method used to estimate a point between 2 given points is called linear interpolation. The approximation method used to estimate a point that does not lie between 2 given points is called linear extrapolation.A linear function has the form f(x) = mx + b. Its graph is a line that has slope m and y intercept at (0,b).

8 0
2 years ago
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What is the standard form of the following equation:
Damm [24]

Answer:

My answer is D) y = 2(x - 2.5)^2 + 6

I hope it helps


7 0
2 years ago
William bought 114 juice boxes for his party. At the end of the party, he had 23 juice boxes left over. How many juice boxes did
slava [35]

Answer:

Number of juice boxes people drank at Williams party = 91

Step-by-step explanation:

Total juice boxes Williams bought = 114

Juice boxes left over at the party = 23

How many juice boxes did people drink at William's party?

Number of juice boxes people drank at Williams party = Total juice boxes Williams bought - Juice boxes left over at the party

= 114 - 23

= 91

Number of juice boxes people drank at Williams party = 91

8 0
2 years ago
Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
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