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yuradex [85]
3 years ago
7

I will rate you brainliest

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

Option (2)

Step-by-step explanation:

In an arithmetic progression,

a_1,a_2,a_3.........a_{n-1},a_n

First term of the progression,

a = a_1

Common difference 'd' = (a_2-a_1)

Recursive formula for the sequence,

a = a_1

a_n=a_{n-1}+d

By applying these rules in the recursive formula,

a_1=\frac{4}{5}

a_n=a_{n-1}+\frac{3}{2}

Common difference 'd' = \frac{3}{2}

Therefore, Option (2) will be the answer.

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Pls help me!!!
Olenka [21]

Answer:

Step-by-step explanation:

A box plot is the diagrammatic representation of the five number summary. It includes 5 items:

The minimum.

Q1 = the first quartile or the 25% mark.

The median.

Q3 = the third quartile or the 75% mark.

The maximum.

Rearranging the data in ascending order, it becomes

169, 163, 153, 166, 149, 148, 146, 145, 152, 163

145, 146, 148, 149, 152, 153, 163, 163, 166, 169

Minimum = 145

Maximum = 169

Median = (152 + 153)/2 = 152.5

The median divides the data into two equal halves. The middle of the lower halve is Q1 while the middle of the upper halve is Q3

Q1 = 148

Q3 = 163

The diagram of the box plot is shown in the attached photo

8 0
3 years ago
Please help me on this! Just one problem to help me solve for x.
nikitadnepr [17]

Answer:


Step-by-step explanation:

cross multiply, \frac{4x + 3(x-1)}{12}\\\\

\frac{4x+3x-3}{12}\\  \\

\frac{7x-3}{12} = 2 + x

7x -3 = 12(2+x)\\\\7x - 3 = 24 + 12x\\\\12x - 7x = -3 - 24\\\\5x = -27 \\\\x = \frac{-27}{5} = -5.4

4 0
3 years ago
Which explicit formula generates the infinite sequence 2, 9, 28, 65, 126, ...?
Dimas [21]
1. The terms of a sequence are denoted by u_{1} ,  u_{2}, u_{3}, u_{4}, u_{5},...

2.
 u_{1}  = 2  = 2*1

  u_{2} = 9 = 3*3
 
u_{3} = 28 = 4*7

u_{4} = 65 = 5*13

u_{5} = 126 = 6*21


3. so it is clear that the first columns add each time by one, and the second column add by 2, then by 4, by 6, by 8 and so on.

4. consider only the second column and how we get the terms, which we will call t_{1} , t_{2}, t_{3}, t_{4}, t_{5},...:

t_{1}=1

t_{2}=1+2

t_{3}=1+2+4=1+2+2*2

t_{4}=1+2+4+6=1+2+2*2+2*3=1+2(1+2+3)

t_{5}=1+2+2*2+2*3+2*4=1+2(1+2+3+4)

5.
So

u_{n}=(n+1)(1+2{1+2+3+....(n-1)})
        
         =(n+1)(1+2 [(n-1)n/2])

         = (n+1)(1+(n-1)n)
       
         =(n+1)( n^{2}-n+1 )


6. We can check: u_{3} = (3+1)( 3^{2}-3+1 )=4*(9-3+1)=4*7=28

7. Remark: Gauss addition formula: 1+2+3+....+n=n(n+1)/2


6 0
4 years ago
Read 2 more answers
Please help!! Solve for n.
Komok [63]

Answer:

n = 9

Step-by-step explanation:

Create equivalent expressions in the equation that all have equal bases, then solve for n.

3 x 3 = 9

Therefore, n = 9

Hope this helps! :D

6 0
3 years ago
Read 2 more answers
2×+2=6<br><img src="https://tex.z-dn.net/?f=5%20x%20%2B%204%20%3D%208" id="TexFormula1" title="5 x + 4 = 8" alt="5 x + 4 = 8" al
amm1812

Answer:

Step-by-step explanation:

hello

2x+2=6 2x+2-2=6-2 \ \ \ substract \ \ 2\\ 2x = 4  \dfrac{2x}{2}=x=\dfrac{4}{2}=2 \ \ \ divide \ \ by  \ \ 2\\

so the solution is 2

5x+4=8 5x+4-4=8-4 \ \ \ substract \ \ 4\\ 5x = 4  \dfrac{5x}{5}=x =\dfrac{4}{5} \ \ \ divide \ \ by  \ \ 5

so the solution is 4/5

hope this helps

3 0
4 years ago
Read 2 more answers
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