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3 years ago

5

On May 22, 1960, an earthquake in Chile measured 9.5 on the Richter scale. On February 27, 2010, another earthquake in Chile mea

sured 8.8 on the Richter scale. Compare the intensities of the two earthquakes. Round to the nearest whole number.

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

5

Step-by-step explanation:

use M = log (StartFraction I Over I Subscript 0 Baseline EndFraction)

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The answer should be 12x cm power of 2

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Simplify and write answer in standard form.

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Answer:

$x^3+8x^2+2x+1$

Step-by-step explanation:

Combine like terms (terms with the same exponent).

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"Standard form" means to list terms so the exponents go from high to low (descending order).

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3 years ago

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Andrei [34K]

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3 years ago

Describe the transformation that takes f(x)=x+1 to g(x) = -x+4. Will Mark Brainliest.

lions [1.4K]

Answer:

Reflection across y axis

Translate up by 3 units

Step-by-step explanation:

Given

$f(x) = x + 1$

$g(x) = -x + 4$

Required

Describe the transformation from f(x) to g(x)

First, take a reflection of f(x) across the y axis.

So f(x) becomes f(-x)

$f(x) = x + 1$ when reflected

$f(-x) = -x +1$

Next, translate f(-x) up by 3 units to give g(x)

$g(x) = f(-x) + k$

Where

$k = 3$

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Reflection across y axis

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3 years ago

Please Identify the congruent triangles in the figure.

Tpy6a [65]

The missing steps are each right angles and $\angle R \cong \angle O$ .

Solution:

Step 1: Given data:

$\overline {P Q} \cong \overline{M N}$

$\overline{Q R} \cong \overline{N O}$

$\overline{P R} \cong \overline{M O}$

Step 2: In the two polygons,

$\angle Q =90^\circ$ and $\angle N =90^\circ$

$\angle Q \cong \angle N$ (Each right angle)

Step 3: Given

$\angle P \cong \angle M$

Step 4: By third angle theorem,

If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.

$\angle R \cong \angle O$

Step 5: By the definition of congruent polygons,

If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.

Hence $\Delta P Q R \cong \Delta M N O$ .

Therefore the missing steps are each right angles and $\angle R \cong \angle O$ .

5 0

3 years ago