All categories

2 years ago

What is the quotient when -45 is divided by -97

Mathematics

2 answers:

defon2 years ago

4 0

Answer:

quotient is 0.4639175258

Step-by-step explanation:

quotient is the result of dividing the two numbers

-45 / -97 = (-1)*45 / (-1)*97= , simplify -1/-1 because equals 1

45/97 = .4639175258 , using the calculator

45/97 =0 R 45, zero is the quotient and 45 is the remainder

dedylja [7]2 years ago

3 0

Answer:

0.463

Step-by-step explanation:

You might be interested in

Factor the following expression 14x + 49

xxTIMURxx [149]

Answer:

7(2x +7)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the value of the expression below? (9-3)+4(6-7) OOOO

allsm [11]

Answer:2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How do I add 1475.48+14.98?

Llana [10]

Answer:1490

Step-by-step explanation:so while solving this question, you want to make sure the decimals are on top of each other. 8+8 is 16 so you write 6 and carry 1. 4+9 is 13 +1 =14, write 4 carry one across the decimals. 5+4 is 9 plus 1 equals 10 write zero carry 1. 7+1 is 8 plus 1 is 9 so you write that down and since 1 and 4 have no numbers under them, you write it down too giving you 1490.46

4 0

3 years ago

The distance between 4 and 17 is

ivanzaharov [21]

17-4= 13
the distance is 13

4 0

3 years ago

Please help

Strike441 [17]

Answer:

The pairs are:

$\frac{4p^3q}{6p^2q^2}\div \frac{12pq^3}{2p^2q^2}$ => $\frac{p^2}{9q^2}$

$\frac{10p^3q^3}{2p^2q}\div \frac{5pq}{6pq^2}$ => $6pq^3$

$\frac{14p^2q^3}{2pq}\div \frac{7p^2q^2}{6p^3q^2}$ => $6p^2q^2$

$\frac{16pq^3}{24p^2q^3}\div \frac{2p^2q^2}{p^3q^3}$ => $\frac{q}{3}$

Step-by-step explanation:

We are going to solve the questions one by one and then write the quotients with every question.

In order to calculate the division, the terms are multiplied then exponents are added or subtracted between numerator and denominator to get the simplest form of answer.

First Expression:

$\frac{4p^3q}{6p^2q^2}\div \frac{12pq^3}{2p^2q^2}$

When two fractions have to be divided the second fraction is reversed i.e. numerator becomes denominator and vice versa.

$= \frac{4p^3q}{6p^2q^2} * \frac{2p^2q^2}{12pq^3}\\=\frac{p^5q^3}{9p^3q^5}\\=\frac{p^2}{9q^2}$

Second Expression:

$\frac{10p^3q^3}{2p^2q}\div \frac{5pq}{6pq^2}$

Removing the division symbol

$=\frac{10p^3q^3}{2p^2q} * \frac{6pq^2}{5pq}\\=\frac{6p^4q^5}{p^3q^2}\\=6pq^3$

Third Expression:

$\frac{14p^2q^3}{2pq}\div \frac{7p^2q^2}{6p^3q^2}$

Removing the division symbol

$=\frac{14p^2q^3}{2pq} * \frac{6p^3q^2}{7p^2q^2}\\= \frac{6p^5q^5}{p^3q^3}\\= 6p^2q^2$

Fourth Expression:

$\frac{16pq^3}{24p^2q^3}\div \frac{2p^2q^2}{p^3q^3}$

Removing the division symbol

$=\frac{16pq^3}{24p^2q^3} * \frac{p^3q^3}{2p^2q^2}\\=\frac{p^4q^6}{3p^4q^5}\\=\frac{q}{3}$

Hence,

The pairs are:

$\frac{4p^3q}{6p^2q^2}\div \frac{12pq^3}{2p^2q^2}$ => $\frac{p^2}{9q^2}$

$\frac{10p^3q^3}{2p^2q}\div \frac{5pq}{6pq^2}$ => $6pq^3$

$\frac{14p^2q^3}{2pq}\div \frac{7p^2q^2}{6p^3q^2}$ => $6p^2q^2$

$\frac{16pq^3}{24p^2q^3}\div \frac{2p^2q^2}{p^3q^3}$ => $\frac{q}{3}$

4 0

3 years ago