Answer: y=4
Step-by-step explanation: First of all, we have to know what a consistent and independent system is.
Consistent and independent- If a consistent system has exactly one solution, and is independent, then it's consistent and independent
Let's graph the equation y=3x-2 first. The y intercept of the equation is -2 and the slope of the equation is 3. Lets plot the y intercept first, then use rise/run for the slope. We end off with the image of the first one I have attached to this answer.
Next, we can see if that we draw a straight arrow to one of the points in the equation, we will get a independent and consistent system. I picked y=4, but you can pick almost any point that lies within the line.
This will grant only one solution, which will give us what we need. So let's graph y=4. Finally, we have our consistent and independent system! I've attached another file to support my answer.
So the final answer to your question is y=4, the solution to the system is (2,4), as you can see by the last image.
<em><u> Give me feedback on my answer. Tell me if I'm lacking explanation about anything. Please help me, you can also help others by informing me what else I need to be specific on.</u></em>
For every 5 green picks, 2 are orange. Adding 5+2 makes 7. 21/7 = 3
There are 3 sets of 5 green 2 orange picks. So 2*3 = 6.
There should be 6 orange picks.
You can also just count. 5 + 2 = 7. Adding another 5 picks = 7 + 5 + 2 = 14. Another 5 picks, 14 + 5 + 2 = 21. Adding up the orange picks, which is the twos, we get 6.
∠n = ∠p
p - 3x = 10
5x - n = 8......> 5x - p = 8
by adding the two equations
2x = 18 , x = 9
p = 37
m∠M = 180 - (2*37) = 106°
Answer:
{x = 2 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
{y = x/2 - 3 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
{-x/2 + y = -3 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{3 x + y = 4 | (equation 1)
{0 x+(7 y)/6 = (-7)/3 | (equation 2)
Multiply equation 2 by 6/7:
{3 x + y = 4 | (equation 1)
{0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 6 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 2 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 2 , y = -2
y = -3x - 2
Since a < 0 we have a decreasing line, so it can be only the first or the last
And if we solve the equation for y = 0 we have
0 = -3x - 2
3x = -2
x = -2/3
So, the last one is the right
