All categories

2 years ago

I need help/ revision of my answer please!

Mathematics

1 answer:

Tresset [83]2 years ago

8 0

Answer:

2 and 3 are correct, not sure if you plan on doing 1, in which case I'd help you

You might be interested in

What is the value of the expression 5ab - 2c, where a = 2, b = 3 and c=0?

Len [333]

Answer:

Step-by-step explanation:

5*2*3-2*0 ( when we multiply any number with zero then the result is also zero)

30-0

5 0

3 years ago

Addison made 11 quarts of punch for her party. How many gallons of punch did she make? THANK YOU ;)

artcher [175]

11 quarts=2.75 gallons. 4 quarts eqals a gallon. Hope that helps!!!!

8 0

2 years ago

F(x) = 5x2 − 70x + 258. Complete the square.

astraxan [27]

5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done

7 0

3 years ago

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

2 years ago

George wishes to increase the percent of acid in 50 ml of a 15% acid solution in water

PtichkaEL [24]

Answer:

screw this question

Step-by-step explanation:

To change from 15% to 25% he needs to add 10%.

If the solution is 50ml then he needs to add 10% which is 5ml... But if he adds 5 ml then the solution will be 55ml total, so that doesn't make sense. He has to take some of the solution that's not acid before adding the 5ml...

3 0

2 years ago

Read 2 more answers