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3 years ago

8

I'm really confused about this problem, I forgot how to do problems like this. I've linked the picture, I could really use some

help, please.

2 answers:

zubka84 [21]3 years ago

5 0

Y = x + 2 should be correct here :)

Lapatulllka [165]3 years ago

3 0

Answer:

y=mx+b

Step-by-step explanation:

You might be interested in

umka2103 [35]

Answer:

The answer is

$7\pi$

Step-by-step explanation:

just remember that the volume of a cylinder is

$v = \pi {r}^{2}h$

8 0

3 years ago

The graph of a linear function is shown on the grid. which equation is best represented by this graph?

hram777 [196]

9514 1404 393

Answer:

D) y - 2 = 5/7(x - 7)

Step-by-step explanation:

The point-slope form of the equation for a line is ...

y -k = m(x -h) . . . . . line with slope m through point (h, k)

The given answer choices are written in point-slope form, so we can see they expect the line to go through one of the points (-7, -2), (7, 3), or (7, 2). Of these, we note that only point (7, 2) is on the line. (eliminates choices A, B, C)

To confirm that choice D is the correct choice, we can look at the slope between the y-intercept of (0, -3) and the point (7, 2). That is ...

m = (y2 -y1)/(x2 -x1)

m = (2 -(-3))/(7 -0) = 5/7

So, the equation of the line is ...

y -2 = 5/7(x -7)

5 0

3 years ago

Please help so i an pass

cestrela7 [59]

Answer:

B. The plant grows 125 mm each week so the slope is 125.

Step-by-step explanation:

I haven't gotten to slopes yet in math.

8 0

3 years ago

A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and

Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

$Hypotenuse^2=Base^2+Perpendicular^2$

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

$(9.85)^2=x^2+(x+5)^2$

$97.0225=x^2+x^2+10x+25$

$0=2x^2+10x+25-97.0225$

$0=2x^2+10x-72.0225$

Here, $a=2, b=10,c=-72.0225$ . Using the quadratic formula, we get

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}$

$x=\dfrac{-10\pm \sqrt{676.18}}{4}$

Approximating the value, we get

$x=\dfrac{-10\pm 26}{4}$

$x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}$

$x=\dfrac{16}{4},\dfrac{-36}{4}$

$x=4,-9$

Distance cannot be negative so $x\neq -9.$

Now we have $x=4$

$x+5=4+5$

$x+5=9$

Therefore, the base is 4 m and the height is 9 m.

5 0

3 years ago

A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates

KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

$P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}$ (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0

3 years ago