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3 years ago

Solve for A if F=MA and F=10 and M=2.5

Mathematics

2 answers:

satela [25.4K]3 years ago

4 0

Answer:A=4

Step-by-step explanation:

10=2.5 X A

10/2.5=4

10=2.5(4)

A=4

gogolik [260]3 years ago

3 0

Answer:

$\boxed{\sf A = 4}$

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

$\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:$

$\sf \implies 10 = 2.5A$

$\sf \implies 2.5A = 10$

$\sf Dividing \ both \ side \ of \ 2.5A = 10 \ by \ 2.5:$

$\sf \implies \frac{2.5}{2.5} A = \frac{10}{2.5}$

$\sf \frac{2.5}{2.5} = 1 :$

$\sf \implies A = \frac{10}{2.5}$

$\sf \frac{4 \times \cancel{2.5}}{ \cancel{2.5}} = 4 :$

$\sf \implies A = 4$

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Blababa [14]

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and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
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Similarly, the partial derivative with respect to $t$ would be found via

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3 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

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2 years ago

A group of 59 randomly selected students have a mean score of 29.5 with a standard

algol [13]

Answer:

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

$\bar X = 29.5$ represent the sample mean

$\mu$ population mean

s= 5.2 represent the sample standard deviation

n=59 represent the sample size

Confidence interval

The confidence interval for the true mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=59-1=58$

The Confidence interval is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value is $t_{\alpha/2}=1.671$

Now we have everything in order to replace into formula (1):

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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2 years ago

What can be concluded if angle 1 =angle7

Maksim231197 [3]

From the information given in the question,
the only possible conclusion is:

If angle 1 is measured and angle 7 is measured,
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If angle 1 and angle 7 are related to a particular shape or drawing,
then additional conclusions may be possible, but we'd need to see
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2 years ago

A college surveys local businesses about the importance of students as customers. The college chooses 150 businesses at

GenaCL600 [577]

The proportion of businesses who did not respond = 54.67%

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The proportion of businesses who did not respond =

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3 years ago