I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
Answer:
C. 10 : 16
Step-by-step explanation:
Attached below
Answer:
0.0143 in decimal form
Step-by-step explanation:
the nearest hundred spot is 700 for the number. when rounding for hundreds, you use the 2nd digit number. Example, if a proablem asks to round 521 to the nearest hundred it would be 500. Another rule to remember is that anything 5 and above you round up (ex: 589 would round up to 600). Anything below 5 you would round down (ex: 234 would round down to 200). goinf back to the problem, the answer should be 7,700
A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median.
The point to the outside of the box is the third quartile.
D is the maximum value.
Hope this helped.
