I need help with 3 4 5

Amelia pays $24 to rent a boat at the lake for up to six hours she constructs the inequality and number line below to represent

liubo4ka [24]

Money= how many hours
$4= 1h
$8=2h
$12=3h
$16=4h
$20=5h
$24=6h
l hope that helps :)

5 0

3 years ago

One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha

Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

$V = 30 \times 30 \times 80$

$V = 72000 cm^3$

to convert this to m^3 we know that 1m = 100cm

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3$

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)$

the cm^3 cancel out.

$V = \dfrac{72000}{100^3} m^3$

$V = 0.072\,m^3$

by simply converting the side-lengths to meters beforehand can give you this answer directly:

$V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3$

it is given that 1 meter cube of water weighs about 2200 pounds.

$1\,m^3 = 2200 \,\text{lb}$

multiply both sides with 0.072 to find our answer:

$1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}$

$0.072\,m^3 = 158.4 \,\text{lb}$

hence the weight of the water in the tank would be 158.4 pounds!

3 0

3 years ago

Sally and Eddy had a total of $580 after spending $80 and eddy had 240 left how much money does Sally have?

levacccp [35]

Answer:

260

Step-by-step explanation:

8 0

3 years ago

Please Hurryyy

Helga [31]

The measure of angle J is 19.8°, and the correct option is D.

<h3>What is the formula of cosine?</h3>

The law of cosine or cosine rule in trigonometry is a relation between the side and the angles of a triangle. Suppose a triangle with sides a, b, c and with angles cosC.

The following formula is used to find the angle j is;

$\rm j^2 = h^2 + i^2 -2hicosC$

Triangle HIJ has side lengths h=12, i = 17, j = 7.

Substitute all the values in the formula;

$\rm j^2 = h^2 + i^2 -2hicosJ\\\\(7)^2=(12)^2+(17)^2-2 \times 12 \times 17 cosJ\\\\49=144+289-408cosJ\\\\144+289 -49 =408cosJ\\\\384 =408cosJ\\\\cosJ=\dfrac{384}{408}\\\\cosj = 0.94\\\\J =cos^{-1}(0.94)\\\\J=19.8$