The manager already hired 9 people. Let be the number of people he still can hire. Since these people will add to the 9 he already hired, when the hiring campaign will be over he will have hired
people. We know that he can't hire more than 14 people, so the number of people hired must be less than or equal to 14:
If we subtract 9 from both sides, we have
so, the manager can hire at most 5 other people
Consider the equation:
Subtracting '4' from both the sides of the equation, we get as
Squaring on both the sides of the equation, we get
Subtracting '2' from both the sides of the equation, we get
x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
Dr. Newton needs 5000 dollars, and 3000 dollars have already been saved. So, 2000 dollars remain.
If these 2000 dollars must be saved withint 8 months, we can divide the amount needed by the time given, to find out that Dr Newton needs to save
dollars each month.