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faust18 [17]
3 years ago
5

Unit rates and ratios need help will give brainiest

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

6

10

3

57

10

Step-by-step explanation:

just divide and find x:1

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11, 12, 13, 14, 15, 16, 17, 18, 19 Sorry if it doesn't help, I'm being too obvious
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PLEASE CAN SOMEONE HELP!!!!!!!!!!!!!!!!<br><br> How can you use subtraction to describe division?
STatiana [176]
Division is repeated subtraction, just like multiplication is repeated addition. If you divide 50 by 10, you get 5. This is also the question: How many times do you have to subtract 10 from 50 to get 0?
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PLEASE HELP DUE IN 15 MINUTES WILL GIVE BRAINLIEST!
AVprozaik [17]

4m = 12x + 40

8x + 8x + 12x + 40 + 4m = 360

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7 0
3 years ago
Hey! i’ll give brainliest pls help.
marta [7]

Answer:

hello there!

The correct option should be the second option and the fourth option!

Step-by-step explanation:

comets usually come from the kuiper belt, and the oort cloud.

anyways, hope this helped! qwq

7 0
3 years ago
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An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
3 years ago
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